The answer is rectangle because the top and bottom sides are long and the sides are sort.
A linear function is a straight line, so that's clearly not it
A quadratic function has one point where is switches from going up to going down (or down to up), but this has two, so that's not it.
A cubic function has 2 points where it goes from down to up or up to down, so this may just work.
An exponential function has a constant to the power of something, so it's either staying constantly up or down after 0 or jumping up and down with every x value, which it isn't doing.
Logarithmic functions are similar to exponential functions in that it usually stays either going up or down the whole time.
Using our definitions, a cubic function is the only one that fits
Answer:
Melinda will paint 5/8 part of a wall when Desiree has finished painting 1 wall.
Step-by-step explanation:
It is given that:
Melinda can paint 1/4 of a wall in the same time that Desiree can paint 2/5 of a wall.
Let 't' be the time taken by Melinda and Desiree to paint 1/4 and 2/5 of a wall respectively.
Now the time taken by Desiree to paint 1 wall will be:
2/5 of wall= t
1 wall= (5/2) t
Now in this time ( i.e. 5/2 t) the part of a wall painted by Melinda will be:
As Melinda takes-- t time to paint= 1/4 of a wall
5/2 t she will paint= (5/2)×(1/4) of a wall= (5/8) of a wall.
Hence Melinda will paint 5/8 part of a wall when Desiree has finished painting 1 wall.
Answer:
Step-by-step explanation:
In this problem, one is given a circle with two secants (that is a line that intersects a circle at two points). One is given certain measurements, the problem asks one to find the unknown measurements.
The product of the lengths theorem gives a ratio between the lengths in the secants. Call the part of the secant that is inside the circle (inside), and the part of the secant between the exterior of the circle and the point of intersection of the secants (outside). The sum of (inside) and (outside) make up the entire secant, call this measurement (total). Remember, there are two secants, (
) and (
) in this situation. With these naming in mind, one can state the product of the length ratio as the following:
Alternatively, one can state it like the following ratio:
Apply this ratio to the given problem, substitute the lengths of the sides of the secants in and solve for the unknown.
Cross products, multiply the numerator and denominators of opposite sides of the fraction together,
Simplify,
Inverse operations,
Substitute this value into the equation given for the measure of (EF),
3 | 1 5 -8 6
. | 3 24 48
- - - - - - - - - - - - - - - -
. | 1 8 16 54
That is to say,
The remainder is 54.
Another way of doing it is to apply the polynomial remainder theorem, which says the remainder upon dividing a polynomial 
by 
is exactly 
. So recognizing that the listed coefficients refer to
we find
