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Studentka2010 [4]
2 years ago
9

What ingredients are used to make chloroform. :p

Chemistry
2 answers:
fenix001 [56]2 years ago
6 0
Bleach, rubbing alcohol or acetone and bleach
mr Goodwill [35]2 years ago
4 0

Answer: i dont no

Explanation:

ddd

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Acetic acid (HC2H3O2) is the active ingredient in vinegar. Calculate the mass percent composition of O in acetic acid.
skelet666 [1.2K]

Answer:

53.29% of acetic acid is Oxygen

Explanation:

Step 1: Given data

Acetic acid it's molecular formula is HC2H3O2. This means it consists of 3 elements Carbon, Hydrogen and oxygen.

Step 2: the molar masses

The molecular mass of acetic acid is:

4* H = 4* 1.01 g/mole

2* C = 2*12 g/mole

2*O = 2* 16 g/mole

Total molar mass = 4+ 24+32 = 60.052 g/mole

Step 3: Calculate the mass percent

32 g of the 60.052 g is Oxygen

(32/60.052) *100% = 53.29%

53.29% of acetic acid is Oxygen.

7 0
3 years ago
Read 2 more answers
What changes are happening to the particles as it changes state from a solid to a liquid?
Bingel [31]

Answer:

A

Explanation:

as something is heated, it gains kinetic energy

3 0
3 years ago
Define combine gas law​
Dennis_Churaev [7]
The combined gas law combines the three gas laws: Boyle's Law, Charles' Law, and Gay-Lussac's Law. It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant. ... The constant k is a true constant if the number of moles of the gas doesn't change.
Hopefully this helps you!
4 0
3 years ago
Read 2 more answers
Compound b (c9h9no4) is a carboxylic acid that has a nitro group attached to an aromatic ring. draw this compound based on its 1
Westkost [7]
The NMR is attached that is required to answer this question. We are told that we have a carboxylic acid and that there is a nitro group directly attached to an aromatic ring. We can begin by determining the substitution on the aromatic ring.

Looking at the NMR spectrum, we a peak that integrates to 1 H at 12 ppm which is characteristic of a carboxylic acid, which we already know is present. Next we have two equivalent doublets that both integrate to 2 H, giving us 4 hydrogens in total. These doublets are in the aromatic region and this type of coupling pattern is characteristic of a 1,4-substituted aromatic ring, so we know there is only one other group substituted on the ring. However, the molecular formula is C₉H₉NO₄, so there are still 2 carbons not accounted for, if we include our carboxlic acid. Therefore, the carboxylic acid must be attached to some alkyl group which is substituted onto the aromatic ring.

We have a doublet at 1.6 ppm that integrates to 3, which suggests this is a methyl group adjacent to a CH. We also have a quartet at 4.0 ppm with an integration of 1. This suggests it is a CH that is adjacent to 3 hydrogen, most likely the methyl group we just described.

Therefore, we have a CH attached to a CH3, so that CH requires two more bonds. The only pieces left to attach to it are the aromatic ring and the carboxylic acid functional group. This gives us the structure shown in the image provided.

8 0
2 years ago
A chemist is studying the rate of the Haber synthesis: N2 + 3H2 2NH3
Slav-nsk [51]

Answer:

1.17 M

Explanation:

Step 1: Write the balanced equation

N₂ + 3 H₂ ⇒ 2 NH₃

Step 2: Calculate the rate of disappearance of H₂

We will use the following expression.

rH₂ = - Δ[H₂]/t = - (0.25 M - 0.50 M)/44 s = 0.0057 M/s

Step 3: Calculate the rate of disappearance of N₂

The molar ratio of N₂ to H₂ is 1:3.

0.0057 mol H₂/L.s × 1 mol N₂/3 mol H₂ = 0.0019 mol N₂/L.s

Step 4: Calculate the final concentration of N₂

We will use the following expression.

[N₂] = [N₂]₀ - rN₂ × t

[N₂] = 1.25 mol/L - 0.0019 mol/L.s × 44 s

[N₂] = 1.17 M

6 0
2 years ago
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