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3 years ago

How does elevation affect the amount of air pressure?”.

Chemistry

1 answer:

Reika [66]3 years ago

5 0

Answer:

Altitude is related to air pressure. As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level. This is what meteorologists and mountaineers mean by "thin air." Thin air exerts less pressure than air at a lower altitude.

Explanation:

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Place the following in order of increasing standard molar entropy H2O(l) H2O(g) H2O(s) a)H2O(S)< H2O(l)

Black_prince [1.1K]

Answer : The order of increasing standard molar entropy is:

$H_2O(s)$

Explanation :

Entropy : It is defined as the measurement of randomness or disorderedness in a system.

The order of entropy will be,

As we are moving from solid state to liquid state to gaseous state, the entropy will be increases due to the increase in the disorderedness.

As we are moving from gaseous state to liquid state to solid state, the entropy will be decreases due to the decrease in the disorderedness.

From this we conclude that the solids have less disorder in the system than liquids because the molecules in the solid are closely or tightly packed as compared to liquid.

The liquids have less disorder in the system than gases because the molecules in the liquid are more close as compared to gases.

That means the more disorderedness in a system, the more will be the entropy.

So, the order of increasing standard molar entropy is:

$H_2O(s)$

7 0

3 years ago

Hurry!! Which feature of the microscope did Anton van Leeuwenhoek add that enabled him to magnify organisms about 250 times?

jek_recluse [69]

Answer: Polished lenses.

Explanation: thats just the answer lol

6 0

4 years ago

Read 2 more answers

1. Determine the volume of a 2 liter container at constant pressure and temperature

PtichkaEL [24]

2 liter

Because the volume is 2 liter and the pressure and temperature are constant so nothing is happening.

6 0

3 years ago

Calculate to three significant digits the density of chlorine pentafluoride gas at exactly and exactly . You can assume chlorine

slega [8]

Answer:

Density is 6.16g/L

Explanation:

... at exactly -15°C and exactly 1atm...

Using general gas law:

PV = nRT

We can find density (Ratio of mass and volume) in an ideal gas as follows:

P/RT = n/V

To convert moles to grams we need to multiply the moles with Molar Weight, MW:

n*MW = m

n = m/MW

P/RT = m/V*MW

P*MW/RT = m/V

Where P is pressure: 1atm;

MW of chlorine pentafluoride: 130.445g/mol

R is gas constant: 0.082atmL/molK

And T is absolute temperature: -15°C+273.15 = 258.15K

Replacing:

P*MW/RT = m/V

1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V

6.16g/L = m/V

<h3>Density of the gas is 6.16g/L</h3>

7 0

3 years ago

A reaction that proceeds by first-order irreversible kinetics is oxidizing chemical A in a wastewater treatment basin with a mea

Wittaler [7]

This question is incomplete, the complete question is;

A reaction that proceeds by first-order irreversible kinetics is oxidizing chemical A in a wastewater treatment basin with a mean residence time of 1.5 hours. The reaction rate constant is 2.0 Hr-1.The basin is unbaffled and may be characterized as two completely mixed tanks in series. If the steady-state influent concentration is 30 mg/l, find the effluent concentration.

If baffles are placed in the basin so that the basin may be characterized as four completely mixed tanks in series, and the mean residence time remains constant, find the effluent concentration.

Answer:

a) (two completely mixed tanks in series) the find the effluent concentration is 4.8 $\frac{mg}{l}$

b) (four completely mixed tanks in series) find the effluent concentration is 3.2 $\frac{mg}{l}$

Explanation:

Given the data in the question;

we can determine the effluent concentration of two completely mixed tanks in series for first order irreversible reaction using the following equation;

C = Co ( 1 / ( 1 + K $\frac{t}{n}$ )ⁿ

t is the mean hydraulic residence time for two completely mixed tanks in series ( 1.5 hr)

Co is initial concentration of the influent ( 30 $\frac{mg}{l}$ )

C is final concentration of effluent,

n is the number of tanks series ( 2)

k is rate constant for the given first order reaction( 2 $\frac{1}{hour}$ )

so we substitute

C = 30 $\frac{mg}{l}$ ( 1 / ( 1 + 2 $\frac{1}{hour}$ . $\frac{1.5}{2}$ )²

C = 30 $\frac{mg}{l}$ × ( 1/2.5)²

C = 30 $\frac{mg}{l}$ × 0.16

C = 4.8 $\frac{mg}{l}$

Therefore, (two completely mixed tanks in series) the find the effluent concentration is 4.8 $\frac{mg}{l}$

using;

C = Co ( 1 / ( 1 + K $\frac{t}{n}$ )ⁿ

t is the mean hydraulic residence time for two completely mixed tanks in series ( 1.5 hr)

Co is initial concentration of the influent ( 30 $\frac{mg}{l}$ )

C is final concentration of effluent,

n is the number of tanks series ( 4)

k is rate constant for the given first order reaction( 2 $\frac{1}{hour}$ )

so we substitute

C = 30 $\frac{mg}{l}$ ( 1 / ( 1 + 2 $\frac{1}{hour}$ . $\frac{1.5}{4}$ )⁴

C = 30 $\frac{mg}{l}$ × ( 1/1.75)²

C = 30 $\frac{mg}{l}$ × 0.107

C = 3.2 $\frac{mg}{l}$

Therefore, (four completely mixed tanks in series) find the effluent concentration is 3.2 $\frac{mg}{l}$

7 0

3 years ago