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shepuryov [24]
2 years ago
6

a 1.912 g samplw of calcium chloride is decomposed and found to contain 0.690 g of Ca and 1.222 g of Cl. Calculate the mass perc

ent composition of Ca in calcium chloride
Chemistry
1 answer:
adoni [48]2 years ago
8 0

Answer:

36.09% is the mass percent composition of calcium in calcium chloride

Explanation:

Mass percent is defined as one hundred times the ratio between the mass of a compound (In this case, Calcium), and the total mass of the sample:

<em>Mass Percent = Mass compound / Total mass of the sample × 100</em>

<em />

Computing the values of the problem:

Mass Percent = 0.690g / 1.912g * 100

Mass percent =

<h3>36.09% is the mass percent composition of calcium in calcium chloride</h3>
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2 years ago
The PH of a solution of Hcl is 2.find out the amount of acid present in a litre of the solution ​
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Answer:

The solution is 10^-2 or 0.01M in HCl.

Explanation:

meaning of pH is "power of hydrogen".

what is the molar concentration of a HCl solution with pH=2?

Let say pH=2

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HCL is a strong acid that dissociates completely:

[H+]=[HCL]

Therefore solution is 10^-2 or 0.01M in HCL.

5 0
3 years ago
30.0 ml of an hf solution were titrated with 22.15 ml of a 0.122 m koh solution to reach the equivalence point. what is the mola
a_sh-v [17]
Answer is: molarity of hydrofluoric solution is 0.09 M.

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V(HF) = 30.0 mL.
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V(KOH) = 22.15 mL:
c(HF) = ?.
From chemical reaction: n(HF) : n(KOH) = 1 : 1.
n(HF) = n(KOH).
c(HF) · V(HF) = c(KOH) · V(KOH).
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8 0
3 years ago
Read 2 more answers
How many grams are in 2.45E24 formula units of Fp3BZ2? The molar mass of Fp3Bz2. is 97.05<br> g/mol.
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Answer:

394.99g

Explanation:

The number of moles of a substance can be calculated by dividing the number of atoms of such substance by Avagadro's number (6.02 × 10^23)

n = nA ÷ 6.02 × 10^23

The number of atoms of Fp3BZ2 in this question is 2.45E24 formula units i.e. 2.45 × 10^24

n = 2.45 × 10^24 ÷ 6.02 × 10^23

n = 2.45/6.02 × 10^(24-23)

n = 0.407 × 10¹

n = 4.07moles

Using mole = mass/molar mass

Where; molar mass of Fp3Bz2. is 97.05

g/mol.

mass = molar mass × mole

mass = 97.05 × 4.07

mass = 394.99g

4 0
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