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erik [133]
3 years ago
10

What is the oxidation number of P in PF6−?

Chemistry
1 answer:
KatRina [158]3 years ago
8 0
Answer:

P = +5

Hope it helps!
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Answer fast my H.W is hard
Marina86 [1]

<u>Answer:</u> The molality of MgF_2 solution is 4.013 m

<u>Explanation:</u>

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg.

The formula used to calculate molarity:

     .....(1)

Given values:

Given mass of MgF_2 = 20.0 g

Molar mass of = 62.3 g/mol

Mass of solvent = 80.0 g

Putting values in equation 1, we get:

\text{Molality of }MgF_2=\frac{20.0\times 1000}{62.3\times 80.0}\\\\\text{Molality of }MgF_2=4.013m

Hence, the molality of MgF_2 solution is 4.013 m

3 0
3 years ago
Does carbon dissolve in water
Damm [24]

Answer:

yes

Explanation:

CO2 is soluble because water molecules are attracted to these polar areas. The bond between carbon

5 0
3 years ago
If m&lt; CAB = 80 degrees, then find m&lt; BAD
eimsori [14]

Answer:

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Explanation:

Just trust me

7 0
2 years ago
Write the expression for the equilibrium constant Kp for the following reaction. (Enclose pressures in parentheses and do NOT wr
Liono4ka [1.6K]

Answer and Explanation:

For the following balanced reaction:

PCl₅(g) ↔ PCl₃(g) + Cl₂(g)

We can see that all reactants and products are gases, so it is an homogeneous equilibrium. The expression for the equilibrium constant Kp can be written from the partial pressures (P) of reactants and products as follows:

Kp=\frac{(P PCl_{3})(P Cl_{2})}{(P PCl_{5})}

Where PPCl₃ is the partial pressure of PCl₃ (reactant), PCl₂ is the partial pressure of Cl₂ (reactant) and PPCl₅ is the partial pressure of PCl₅ (product).

6 0
2 years ago
How much heat do you need to raise the temperature of 150 g of ice from -30°C to -15°c?
OLga [1]
To solve this question, you must use the formula: q=mc(change in temperature), where q is heat, m is mass, C is specific heat and temperature change is temperature change. The specific heat for ice is 2.1kJ/Kg x K (given). The change in temperature is 15 degrees Celsius (which you should change to kelvins so you can cancel out units), or 273 + 15 = 288K. The mass is 150 grams, which is 0.15 kg. Now, we can solve for q, heat. We will do this by substituting variables into the formula. After simplifying and cancelling out units, the answer we get is: 90.72kJ.
4 0
3 years ago
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