First convert grams to moles
using molar mass of butane that is 58.1 g
3.50g C4H10 x (1 mol
C4H10)/(58.1g C4H10) = 0.06024 mol C4H10 <span>
<span>Now convert moles to molecules by using Avogadro’s number
0.06024 mol C4H10 x (6.022x10^23 molecules C4H10)/(1 mol
C4H10) = 3.627x10^22 molecules C4H10
And there are 4 carbon atoms in 1 molecule of butane, so use
the following ratio:
3.627 x 10^22 molecules C4H10 x (4 atoms C)/(1 molecule
C4H10)
<span>= 1.45 x 10^23 atoms of carbon are present</span></span></span>
Answer: Sustainable living
Explanation: It is a lifestyle by which an individual uses natural resources only as much as is necessary, which means in limited quantities, and thus reduces the general enormous exploitation of these resources. In this way, the needs of the individual are met and resources are put to use for generations to come. It also refers to personal resources as well as Earth resources in general.
It is obvious from today's point of view that if food was produced only as much as needed, it would mean not throwing away food, everyone, both those who could otherwise afford food and those who are now starving, would be fed up.
With the reduction of production not only of food but also of other necessities, that is, with production to meet the needs and not beyond, there would be less pollution and less emission of harmful hags and greenhouse effect.
Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.
Answer:
0.912 mL
Explanation:
3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)
FeCl3 is the limiting reactant.
Number of moles of iron III sulphide produced= 3.75g/87.92 g/mol = 0.043 moles
Hence actual yield of Iron III sulphide = 0.043 moles
Theoretical yield of Iron III sulphide = actual yield ×100%/ %yield
Theoretical yield of iron III sulphide= 0.043 ×100/75 = 0.057 moles of Iron III sulphide
From the reaction equation,
2moles of iron III chloride produced 1 mole of iron III sulphide
x moles of iron III chloride, will produce 0.057 of iron III sulphide
x= 2× 0.057= 0.114 moles of iron III chloride
But
Volume= number of moles/ concentration
Volume= 0.114/0.125
Volume= 0.912 mL
Answer:
Subtract the mass of the CuSO4⋅ 5H2O from the mass of CuSO4 is the right one
