What is the oxidation number of P in PF6−?

Which statement best describes the effects chemicals may have on the

frutty [35]

The answer is B. So yeah

7 0

2 years ago

recheck Fusion reactions power the in space. Humans currently use fusion in , but researchers are seeking more applications.

quester [9]

One: looks to be correct for both answers. Certainly the first one is. The second depends on your other choices. But military use is one.

Two: is correct. Pd has (in this case) an atomic mass of 114 and its number is 46

Three: Even with my slop numbers, 4.98 is the answer (although I get 4.99 but again, my numbers are pretty sloppy).

Four: Slop numbers say 78.3, but 78 is the right answer.

Five: Slop numbers agree with Al2S3. I think that's D

They are all correct. Very Fine Work.

4 0

2 years ago

Write balance complete molecular equation, ionic equation, and net ionic equations for the reactions that occur when each of the

AveGali [126]

<u>Answer:</u> The complete molecular, ionic, and net ionic equations are given below. The spectator ions are sodium and nitrate ions.

<u>Explanation:</u>

The ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.

The net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

The balanced molecular equation for the reaction of lead (II) nitrate and sodium sulfide follows:

$Pb(NO_3)_2(aq)+Na_2S(aq)\rightarrow PbS(s)+2NaNO_3(s)$

The ionic equation follows:

$Pb^{2+}(aq)+2NO_3^-(aq)+2Na^+(aq)+S^{2-}(aq)\rightarrow PbS(s)+2Na^+(aq)+2NO_3^-(aq)$

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

$Pb^{2+}(aq)+S^{2-}(aq)\rightarrow PbS(s)$

3 0

2 years ago

A solution labeled "0.105 M NaOH" would contain ______________ moles of NaOH in each liter of solution.

dem82 [27]

Answer:

A solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.

Explanation:

The concentration of a solution in Molarity (M) stands for the number of moles of that substance contained in 1 L of solution.

Molarity = Concentration in mol/L = (Number of moles of solute) ÷ (Volume of solution in L)

Molarity = Concentration in mol/L = 0.105 M = 0.105 mol/L

Number of moles of solute = ?

Volume of solution in L = 1 L

0.105 = Number of moles of solute × 1

Number of moles of solute = 0.105 mole

Hence, a solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.

Hope this Helps!!!

7 0

2 years ago

You are given 25.00 mL of an acetic acid solution of unknown concentration. You find it requires 35.75 mL of a 0.1950 M NaOH sol

oee [108]

Answer:

0.2788 M

1.674 %(m/V)

Explanation:

Step 1: Write the balanced equation

NaOH + CH₃COOH → CH₃COONa + H₂O

Step 2: Calculate the reacting moles of NaOH

$0.03575 L \times \frac{0.1950mol}{L} = 6.971 \times 10^{-3} mol$

Step 3: Calculate the reacting moles of CH₃COOH

The molar ratio of NaOH to CH₃COOH is 1:1.

$6.971 \times 10^{-3} molNaOH \times \frac{1molCH_3COOH}{1molNaOH} = 6.971 \times 10^{-3} molCH_3COOH$

Step 4: Calculate the molarity of the acetic acid solution

$M = \frac{6.971 \times 10^{-3} mol}{0.02500L} =0.2788 M$

Step 5: Calculate the mass of acetic acid

The molar mass of acetic acid is 60.05 g/mol.

$6.971 \times 10^{-3} mol \times \frac{60.05g}{mol} =0.4186 g$

Step 6: Calculate the percentage of acetic acid in the solution

$\frac{0.4186g}{25.00mL} \times 100\% = 1.674 \%(m/V)$

6 0

2 years ago

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