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erik [133]
3 years ago
10

What is the oxidation number of P in PF6−?

Chemistry
1 answer:
KatRina [158]3 years ago
8 0
Answer:

P = +5

Hope it helps!
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Predict whether carbon dioxide or water would have a higher boiling point. Explain your prediction in terms of the attractions b
yulyashka [42]

Answer:

since ionic bonds, bonds that are charged, have very high boiling points, then the water would have a higher boiling point because it has a slight charge whereas carbon dioxide is stable.

Explanation:

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MgSO4 x 7H2O:
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Answer:In regards to writing the formula, we know that magnesium has a charge of 1+ and sulfate, SO4, has a charge of 1-. Sulfate is a polyatomic ion so the charge of the whole thing is (SO4)1-. When you combine them you end up with MgSO4 and the "heptahydrate" is seven water molecules.

Explanation:

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The hydrogens and oxygen of a water molecule are held together by ______ bonds.
umka2103 [35]
The hydrogens and oxygen of a water molecule are held together by covalent bond
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A(n) _____ is a natural object that orbits another object in the solar system besides the Sun.
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The answer is the moon

4 0
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1. The most useful ore of aluminum is bauxite, in which Al is present as hydrated oxides, Al2O3⋅xH2O The number of kilowatt-hour
lianna [129]

*Answer:

Option A: 59.6

Explanation:

Step 1: Data given

Mass of aluminium = 4.00 kg

The applied emf = 5.00 V

watts = volts * amperes

Step 2: Calculate amperes

equivalent mass of aluminum = 27 / 3 = 9  

mass of deposit = (equivalent mass x amperes x seconds) / 96500

4000 grams = (9* amperes * seconds) / 96500

amperes * seconds = 42888888.9

1 hour = 3600 seconds

amperes * hours = 42888888.9 / 3600 = 11913.6

amperes = 11913.6 / hours

Step 3: Calculate kilowatts

watts = 5 * 11913.6 / hours

watts = 59568 (per hour)

kilowatts = 59.6 (per hour)

The number of kilowatt-hours of electricity required to produce 4.00kg of aluminum from electrolysis of compounds from bauxite is 59.6 kWh when the applied emf is 5.00V

5 0
3 years ago
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