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nevsk [136]
3 years ago
9

HELP

Mathematics
2 answers:
Gemiola [76]3 years ago
6 0

x=3

z=-4

n=11/5

r=26/3

t=-4

hope this helps

ziro4ka [17]3 years ago
4 0

Answer:

Z = -4

Step-by-step explanation:

Simplifying

53 = -19z + 5 + 7z

Reorder the terms:

53 = 5 + -19z + 7z

Combine like terms:

-19z + 7z = -12z

53 = 5 + -12z  

Solving

53 = 5 + -12z

Move all terms containing z to the left, all other terms to the right.

Add '12z' to each side of the equation.

53 + 12z = 5 + -12z + 12z

Combine like terms:

-12z + 12z = 0

53 + 12z = 5 + 0

53 + 12z = 5

Add '-53' to each side of the equation.

53 + -53 + 12z = 5 + -53

Combine like terms: 53 + -53 = 0

0 + 12z = 5 + -53

12z = 5 + -53

Combine like terms: 5 + -53 = -48

12z = -48

Divide each side by '12'.

z = -4

Simplifying

z = -4

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astra-53 [7]

Answer:

Step-by-step explanation:

1/2 * ( 9 * 6 * 10)

1/2 * 540

270 in^{2}

7 0
3 years ago
Which equation describes how the parent function y=x^3, is vertically streched by a factor of 4
Murljashka [212]

Answer:

y=4x^{3}

Step-by-step explanation:

It is known that,

<em>'Vertical stretch, stretches the function up and down towards the y-axis'.</em>

The general form of vertical stretch is given by 'kf(x)', where k>1 is the factor by which function is stretched.

As, we have the function y=x^{3} which is stretched by a factor of 4.

Thus, the new function will be y=4x^{3}.

Hence, the equation for the vertical stretch is y=4x^{3}.

8 0
3 years ago
This would be SSS correct ?
AfilCa [17]

Answer:

Yes

Step-by-step explanation:

I think so

8 0
3 years ago
Read 2 more answers
rhombus and a square have one and the same side of 6 cm. The area of the rhombus is 4/5 of the area of the square. Find the heig
siniylev [52]
Consider this option:
1. area_rombus=a*h, where a=6 - the length of the side, h - height.
h=area_rombus/a.
2. area_sq=a², where a=6 - the length of the square.
area_sq=36, area_rombus=4/5 *36=28.8.
3. according to the item 1 h=area_rombus/a=28.8/6=4.8.

answer: 4.8
6 0
3 years ago
the initial term of arithmetic sequence is 5. The eleventh term is 125. what is the common difference of the arithmetic sequence
kap26 [50]
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
-
f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.



4 0
3 years ago
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