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Zina [86]
4 years ago
8

Electricity problem (coulomb's law)

Physics
1 answer:
ICE Princess25 [194]4 years ago
7 0
Coulomb's Law: The interaction between charged objects is a non-contact force that acts over some distance of separation.
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Does voltage flow in a circuit? Explain
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Voltage is the measure of specific potential energy (potential energy per unit charge) between two locations. ... When a voltage source is connected to a circuit, the voltage will cause a uniform flow of charge carriers through that circuit called a current.

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You are looking at a yellow flower growing outside in the sunshine. Why does it look yellow?
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It looks yellow because that is the only (major) color reflected.

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nitially, scientists described atoms as the smallest particles of matter. However, smaller particles within atoms were discovere
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<h2>Answer</h2>

They get involved in this new information

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In the ancient time, the scientists believed that there is the smallest particle which can control the nature of reaction in the environment which they called them. Then a lot of experiment was conducted in which new coming scientists discovered the protons, electrons, neutrons, and other smallest particles. Firstly, scientists performed experiments for this new discoveries to know better about them and then include them in their next experiment for better exposures.

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4 years ago
It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This in
Vladimir [108]

Answer:

v=4m/s

Explanation:

The formulas for accelerated motion are:

v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}

We can derive the formula v^2=v_0^2+2ad from them.

We have:

v-v_0=at\\t=\frac{v-v_0}{a}

And substitute:

x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}\\2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2

Where in the first step of the last row we just multiplied everything by 2a. Since x-x_0 is the displacement d, we have proved that v^2=v_0^2+2ad

We use then our values to calculate the final velocity when starting from rest, traveling a distance 0.002m with acceleration 4000 m/s^2:

v=\sqrt{v_0^2+2ad}=\sqrt{2(4000m/s^2)(0.002m)}=4m/s

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3 years ago
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