Answer A is correct - m1l
Answer:
(D) Vf² = Vi² + 2ad
a = 2.269 m/s²
Explanation:
Given;
final velocity of the aircraft, Vf = 33 m/s
initial velocity of the aircraft, Vi = 0
distance traveled by the plane, d = 240 m
The acceleration of the plane is given by the following kinematic equation;
Vf² = Vi² + 2ad
where;
a is the acceleration;
Based on the given options, the correct option is "D".
Calculating the acceleration with the chosen equation;
Vf² = Vi² + 2ad
Vf² = 0+ 2ad
Vf² = 2ad
a = Vf² / 2d
a = (33)² / (2 x 240)
a = 2.269 m/s²
The speed of light in that medium is .
<u>Explanation:</u>
It is known that the light's speed is constant when it travels in vacuum and the value is . When the light enters another medium other than vacuum, its speed get decreased as the light gets refracted by an angle.
The amount of refraction can be determined by the index of refraction or refractive index of the medium. The refraction index is measured as the ratios of speed of light in vacuum to that in the medium. It is represented as η =
So, here η is the index of refraction of a medium which is given as 1.4, c is the light's speed in vacuum () and v is the light's speed in that medium which we need to find.
Thus the speed of light in that medium is
Using equation you can solve
When car is at the top of the hill its whole energy is stored in the form of gravitational potential energy
so when height of the car becomes half then its potential energy is given as
so final potential energy when car falls down by half of the height will become half of the initial potential energy
So it is U = 50 MJ after falling down
Now by energy conservation we can say that final potential energy + final Kinetic energy must be equal to the initial potential energy of the car
So here at half of the height kinetic energy of car = 100 - 50 = 50 MJ
so we can say at this point magnitude of potential energy and kinetic energy will be same
<em>A. the same as the potential energy at that point.</em>