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givi [52]
3 years ago
8

How many meters are in 32 kilometers

Physics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

32,000 m

Explanation:

Conversion

1km ===> 1000m

32km===>x

x = (32 × 1000) ÷ 1

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The bands on Jupiter are ultimately caused by...
Margaret [11]
Precision because it’s the answer
7 0
3 years ago
How many water (in kg) can raise its temperature from 23°C to 100°C by adding 21500 Joules of energy?
igomit [66]

Answer: Approximately 8.0g of water

Explanation:

4 0
3 years ago
) It is necessary to maintain a constant fluid volume in the body. Therefore, the body adjusts the water outputs to be equal to
loris [4]

Answer:

Evaporative Water Loss = 2 kg

Explanation:

According to the given condition, the water entering the body must be equal to the water leaving the body. Therefore,

Water Entering the Body = Water Leaving the Body

Feed Water + Drinking Water + Metabolic Water = Urine Water + Evaporative Water Loss

using the given values:

1 kg + 5 kg + 0.5 kg = 4.5 kg + Evaporative Water Loss

Evaporative Water Loss = 1 kg + 5 kg + 0.5 kg - 4.5 kg

<u>Evaporative Water Loss = 2 kg</u>

8 0
3 years ago
The spacing between the plates of a 1.0 μF capacitor is 0.050 mm. a) What is the surface area of the plates? b) How much charge
nataly862011 [7]

Answer:

(a) surface area of the plate will be equal to 1.129m^2

(b) Charge on the capacitor is equal to 1.5\times 10^{-6}C

Explanation:

We have given spacing between the plates d = 0.05 mm = 5\times 10^{-5}m

Value of capacitance C=1\mu F=10^{-6}F

(A) Capacitance of a parallel plate capacitor is equal to C=\frac{\epsilon _0A}{d}

So 10^{-6}=\frac{8.85\times 10^{-12}\times A}{10^{-5}}

A=1.129m^2

So surface area of the plate will be equal to 1.129m^2

(B) It is given that capacitor is charged by 1.5 volt

So voltage V = 1.5 volt

Charge on the capacitor is equal to Q=CV

So Q=1.5\times 10^{-6}C

5 0
3 years ago
Anyone know how to do this?
MrMuchimi

The voltage from one side of the battery all the way around to the other side of the battery is 12v .

If 4 of those volts show up across the circle-thing, then the rest of the 12v ... 8v ... Must show up across the set of parallel rectangles.

To get that answer, I subtracted the 4 from the 12.

Just like it says in choice-C.

7 0
3 years ago
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