Lewis structures of the products has been given in below attachment
Methylamine acts as a bronsted-lowry acid by donating proton and water acts as a bronsted-lowry base by accepting proton.
The mechanism involves attack by lone pair on oxygen atom in water molecule towards proton attached to nitrogen atom in methylamine.
The mechanism has been shown below.
Here is the procedure to know how to get those kg of ammonia
Molar mass of (NH4)2SO4 = (14.0 + 1.0x4)x2 + 32.1 + 16.0x4 = 132.1
No. of mole of (NH4)2SO4 =mass/ molar mass = 1x10^5 x 1000 / 132.1 = 757002.271 mole
No. of mole of ammonia needed = No. of mole of (NH4)2SO4 = 757002.271 mole
Mass of ammonia needed = 757002.271 x mole mass of NH3
= 757002.271 x (14.0 + 1.0x3)
= 757002.271x 17.0
= 12869038.61 g
= 1.29 x10^4 kg</span>
The answer is either A or C. Sorry I'm not much help :)
<span>37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2
4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
2 mole x 6.023x 10^23atoms/mole =12.04 atoms