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Katyanochek1 [597]
3 years ago
10

At constant pressure, the combustion of 5.00 g of c2h6(g) releases 259 kj of heat. what is δh for the reaction given below? 2 c2

h6(g) + 7 o2(g) → 4 co2(g) + 6 h2o(l).
Chemistry
2 answers:
LekaFEV [45]3 years ago
7 0

Answer:

-3108 kJ

Explanation:

Because the combustion is releasing heat, the reaction is exothermic, and because of that, the value of the enthalpy must be negative. When a reaction absorbs heat it is endothermic and the enthalpy is positive.

By the reaction given, there are 2 moles of C₂H₆ reacting. The molar mass of the compound is:

2* 12 g/mol of C + 6* 1 g/mol of H = 30 g/mol

So, 2 moles have 60 g (2mol * 30g/mol).

5.00 g --------------- -259 kJ

60 g --------------- δh

By a simple direct three rule:

5δh = -15540

δh = -3108 kJ

Nonamiya [84]3 years ago
3 0

3120 kJ

<h3>Further explanation</h3>

Given:

At constant pressure, the combustion of 5.00 g of C₂H₅  releases 259 kJ of heat.

Question:

What is ΔH for the reaction given below?

\boxed{ \ 2C_2H_6_{(g)} + 7O_2_{(g)} \rightarrow 4CO_2_{(g)} + 6H_2O_{(l)} \ }.

The Process:

Step-1

  • Relative atomic mass: C = 12.01 and H = 1.008
  • Relative molecular mass (Mr) of C₂H₅ = 2(12.01) + 6(1.008) = 30.07 g/mol

Step-2

Let us convert mass to mol of 5 g of C₂H₅.

\boxed{ \ n = \frac{mass}{Mr} \ } \rightarrow \boxed{ \ n = \frac{5}{30.07} \ } \rightarrow \boxed{ \ n = 0.166 \ moles \ }

Remember, the combustion of 0.166 moles of C₂H₅ releases 259 kJ of heat.

Step-3

Combustion reactions that release heat into the environment, including the type of exothermic reaction. The exothermic reaction has a negative ΔH because the product enthalpy is lower than the reactant enthalpy of the system.

And now, we will solve the problem of what is ΔH for the reaction given below.

\boxed{ \ 2C_2H_6_{(g)} + 7O_2_{(g)} \rightarrow 4CO_2_{(g)} + 6H_2O_{(l)} \ }

Notice that 2 moles of C₂H₅ take part in this reaction.

\boxed{ \ \Delta H = \frac{2 \ moles}{0.166 \ moles} \times (-259 \ kJ) \ }

\boxed{ \ \Delta H = 12.048 \times (-259 \ kJ) \ }

\boxed{ \ \Delta H \approx - 3120 \ kJ \ }

Thus, the combustion of C₂H₅ based on the equation of reaction above releases heat of 3120 kJ.

<h3>Learn more</h3>
  1. How much energy is required to vaporize 98.6 g of ethanol (C₂H₅OH) at its boiling point brainly.com/question/4035699
  2. How many moles of O₂ are required for the complete reaction of combustion of C₂H₄ brainly.com/question/3609972  
  3. Calculate the enthalpy change per mole of ethylene combusted brainly.com/question/9360310
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The partial atmospheric pressure (atm) of hydrogen in the mixture is 0.59 atm.

<h3>How do we calculate the partial pressure of gas?</h3>

Partial pressure of particular gas will be calculated as:

p = nP, where

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the pressure in a sealed plastic container is 108 kPa at 41 degrees Celsius. What is the pressure when the temperature drops to
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<u>Answer:</u> The new pressure will be 101.46 kPa.

<u>Explanation:</u>

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

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where,

P_1\text{ and }T_1 are initial pressure and temperature.

P_2\text{ and }T_2 are final pressure and temperature.

We are given:

By using conversion factor:   T(K)=T(^oC)+273

P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K

Putting values in above equation, we get:

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Hence, the new pressure will be 101.46 kPa.

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