Answer:
Mass = 53.45 g
Explanation:
Given data:
Mass of propane = 200 g
Mass of S₂ = 75 g
Theoretical yield /Mass of CS₂ = ?
Solution:
Balanced Chemical equation:
C₃H₈ + 5S₂ → 4H₂S + 3CS₂
Number of moles of propane:
Number of moles = mass / molar mass
Number of moles = 200 g/ 44.1 g/mol
Number of moles = 4.54 mol
Number of moles of S₂:
Number of moles = mass / molar mass
Number of moles = 75 g/ 64.14 g/mol
Number of moles = 1.17 mol
Now we will compare the moles of carbon disulfide with both reactant.
S₂ : CS₂
5 : 3
1.17 : 3/5×1.17 = 0.702
C₃H₈ : CS₂
1 : 3
4.54 : 3×4.54 = 13.62 mol
Number of moles of CS₂ produced by S₂ are less so it will limiting reactant and limit the yield of carbon disulfide.
Theoretical yield of carbon disulfide.
Mass = number of moles ×molar mass
Mass = 0.702 mol × 76.14 g/mol
Mass = 53.45 g
Answer:
TIMED HELP ASAP
19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g･°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.
Answer:
Option D: it's ability to lose electrons
Explanation:
Alkali metals are usually discovered in nature. They have highly reactivity at STP conditions (standard temperature and pressure conditions) and easily lose their outermost electron to form positive ions known that have a charge of +1.
Thus, what can determine the extent of reactivity of an alkali metal, is it's ability to lose electrons
Since the total amount of valence electrons is 3, it is in group 13 in the periodic table..therefore, it is specified as Boron.✅
