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olga nikolaevna [1]
2 years ago
14

For the balanced equation shown below, what would be the limiting reagent if 80.2 grams of N2 were reacted

Chemistry
1 answer:
Leto [7]2 years ago
3 0

Kill him or PS5? Which one?

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Balance the equation and write the reaction-quotient expression, qc. u(s) + f2(g) ----> uf6(g)
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The equation presented above is that of uranium reacting with fluorine forming uranium fluoride. 

The chemical reaction can be balanced by carefully studying the equation and balancing the number of atoms of each of the element in both sides of the chemical reaction. That is,
 
                  <em>         U(s) + 3F₂(g) --> UF₆(g)</em>
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Air is made up of different gases, such as oxygen, nitrogen, and carbon dioxide. Which statement best describes these three comp
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2 years ago
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The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat
WINSTONCH [101]

Answer:

Final temperature = 43.53^{\circ} C

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1

Put all the values,

T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C

So, the final temperature is equal to 43.53^{\circ} C.

8 0
3 years ago
How would you prepare 100.0 ml of.400 m CaCl2 from a stock solution of 2.00 M CaCl2?
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C₀=2 mol/l
c₁=0.400 mol/l
v₁=100.0 ml = 0.1 l

c₁v₁=c₀v₀

v₀=c₁v₁/c₀
v(H₂O)=v₁-v₀

v₀=0.1*0.400/2=0.02 l = 20 ml
v(H₂O)=100 - 20 = 80 ml

It is necessary to mix 20 ml of the feed solution and 80 ml of water.

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3 years ago
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