Answer:
a. CH3NH2(aq) + H⁺ → CH3NH3⁺
Explanation:
The mixture of a weak base as CH3NH2 with its conjugate acid CH3NH3Cl produce a buffer. As the weak acid is in equilibrium with water, the mixture of the weak base and its conjugate base produce that the acid or base released react avoiding the change in pH.
For example, when a strong acid as HNO3 reacts, the weak base will react producing the conjugate base, that is:
CH3NH2(aq) + H⁺ → CH3NH3⁺
Right answer is:
<h3>a. CH3NH2(aq) + H⁺ → CH3NH3⁺</h3>
Mass of aluminum = (1.50 m^3)( 2.70 x 10^3 kg/m^3) = 4050 kg
The intention of density is the assembly per volume of the substance. This is an intrinsic property consequently the size (or any external feature) does not change this effects.
<h3>What is Aluminum?</h3>
- Aluminum is a silvery-white metal, the 13 elements in the regular table. One surprising fact regarding aluminum is that it's the most widespread metal on Earth, making up more than 8% of the Earth's core mass. It's also the third most standard chemical essence on our planet after oxygen and silicon.
- The formed aluminum is in everyday use in mining, manufacturing, and trade in the United States; the formed aluminum is used with reasonable uniformity in Great Britain and typically by chemists in the United States.
- Aluminum (Al), also spelled aluminum, chemical component, a weightless silvery-white metal of main Group 13 (IIIa, or boron group) of the periodic table. Aluminum is the most plentiful metallic component in Earth's crust and the numerous widely used nonferrous metal.
To learn motrev about Aluminum, refer to:
brainly.com/question/246454
#SPJ4
<h3>
Answer:</h3>
8CO₂
<h3>
Explanation:</h3>
We are given;
- Butane is a hydrocarbon in the homologous series known as alkane.
We are required to determine the other product produced in the combustion of butane apart from water.
- We know that the complete combustion of alkane yields carbon dioxide and water.
- Therefore, combustion of butane will yield carbon dioxide and water.
- The balanced equation for the complete combustion of butane will be;
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O
Answer:
p-fluoronitrobenzene and sodium phenoxide is more appropriate
Explanation:
An ipso substitution is required to form p-nitrophenyl phenyl ether.
For this ipso substitution, an alkoxide anion needs to attack as a nucleophile at the carbon atom attached to fluorine atom and thereby substitute that F atom.
p-nitrophenoxide is an weak nucleophile as compared to phenoxide due to presence of electron withdrawing resonating effect of nitro group at para position.
p-fluoronitrobenzene is a good choice for nucleophilic attack by alkoxide anion as compared to fluorobenzene due to higher positive charge density at carbon atom directly attached to F atom. Higher positive charge density arises due to presence of electron withdrawing resonating effect og nitro group at para position.
So, p-fluoronitrobenzene and sodium phenoxide is more appropriate
Staining specimen with heavy metal salts (e.g. tungsten, molybdenum) allows you to see the specimen better with higher contrast when electron beam deflects off of your sample.
