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Oksana_A [137]
3 years ago
12

What is The particle in the nucleus of an atom that has the same mass of protons but no net charge

Chemistry
1 answer:
vichka [17]3 years ago
7 0

Answer:

neutron

Explanation:

neutron and proton has approximately the same mass .proton is positively charged but neutron has no charge

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Use the given data at 500 K to calculate ΔG°for the reaction
Anton [14]

Answer : The  value of \Delta G^o for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]

\Delta H^o=-1035.6kJ=-1035600J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]

\Delta S^o=-153J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 500 K.

\Delta G^o=(-1035600J)-(500K\times -153J/K)

\Delta G^o=-959100J=-959.1kJ

Therefore, the value of \Delta G^o for the reaction is -959.1 kJ

3 0
3 years ago
Exactly how many -OH groups are found in a 6 carbon alditol?
mr Goodwill [35]

Answer:

The number of  OH group found in found in a 6 carbon alditol is  6

Explanation:

The  structure of a 6 carbon alditol is shown on the first uploaded image

8 0
3 years ago
An aqueous solution of ____ will produce a basic solution.
Anastasy [175]
NaClO, K2CO3, and NaF will form basic soltions.

6 0
3 years ago
Read 2 more answers
Tetrachloromethane,CC15,is classified as a
prohojiy [21]
Correct Answer: compound because the atoms of the elements are combined in a fixed proportion.
7 0
3 years ago
Solutions can only be separated by using distillation not filtration. Why can't a solution be filtered? Explain using the terms
garri49 [273]
<h2>Solutions</h2>

Explanation:

  • Solutions are formed when a solute gets dissolved in a solvent. The solid that gets dissolved is called solute whereas the liquid in which the solid gets dissolved is called the solvent. On dissolving,  the particles of the solute  gets incorporated between the inter-particle space of the solvent. This means that there is no significant difference between the particle size of solute and solvent. However the boiling points of solutions can differ significantly. This is the reason, the solutions cannot be separated by the method of filtration but by the method of distillation.
5 0
3 years ago
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