3 years ago

How do you write the quotient of 3 and the total of 4 and a number

Mathematics

1 answer:

marta [7]3 years ago

3 0

3 divided by (4 + n). Hope it helps! :)

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Find the standard form of the circle x2 + y2 – 6x + 10y + 24 = 0 by completing the square.

hichkok12 [17]

Answer:

$(x-3)^2+ (y+5)^2=10$

Step-by-step explanation:

Given the equation of the circle: $x^2 + y^2 - 6x + 10y + 24 = 0$

We wish to express it in a Standard form:

We begin by re-arranging:

$x^2 - 6x + y^2 + 10y = - 24$

Next, divide the coefficient of x by 2, square it and add it to both sides.

Do the same for y.

$x^2 - 6x +(-3)^2+ y^2 + 10y+5^2 = - 24+(-3)^2+5^2$

Next, we factorize

$(x-3)^2+ (y+5)^2 = - 24+9+25\\(x-3)^2+ (y+5)^2=10$

This is the standard form.

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3 years ago

The scores on a test are normally distributed with a mean of 210 and a standard deviation of 20. What is the score that is 1 dev

telo118 [61]

Answer:The score above the mean is 50 percent.

Step-by-step explanation:

8 0

1 year ago

Use synthetic division to find the quotient and remainder of (3x^4-8x^3+9x+5) ÷ (x-2)<br>

Rudiy27

Answer:

3x^3-2x^2-4x+1+7/x-2

Step-by-step explanation:

btw I used something called m a t h w a y it helps alot

3x^3-2x^2-4x+1+7/x-2

I tried

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3 years ago

How do I solve this question?

Murrr4er [49]

Eenbejejejejrhrbeueiiwjsjdje

6 0

3 years ago

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Factor the polynomial below.

OverLord2011 [107]

Answer:

option-A

Step-by-step explanation:

we are given

$6b^2+3b$

we can factor each terms

and then we can take common terms among them

$6b^2=2\times 3\times b\times b$

$3b=1\times 3\times b$

we can replace it

and we get

$6b^2+3b=2\times 3\times b\times b +1\times 3\times b$

now, we can take out common terms

we can see that common terms are 3 and b

$6b^2+3b=3b(2\times b+1)$

we can simplify it

$6b^2+3b=3b(2b+1)$

8 0

3 years ago

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