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3 years ago

A sound wave in the air has a frequency of 256 hertz and is traveling at a speed of 331 meters/second. What is its wavelength?

Physics

2 answers:

nikdorinn [45]3 years ago

6 0

2.39 is the answer cuh

emmainna [20.7K]3 years ago

6 0

Answer: The correct answer is 1.29 m/s.

Explanation:

The expression for the velocity of the wave is as follows;

$v=f\lambda$

Here, f is the frequency of the wave, v is the velocity of the wave and $\lambda$ is the wavelength of the wave.

It is given in the problem that a sound wave in the air has a frequency of 256 hertz and is traveling at a speed of 331 meters/second.

Calculate the wavelength of the wave by rearranging the above expression.

Put v= 331 m/s and f= 256 Hz by rearranging the above expression.

$\lambda =\frac{331}{256}$

$\lambda =1.29 m$

Therefore, the wavelength of the wave is 1.29.

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Problem 21-40a:

Greeley [361]

Answer:

Part a)

$\frac{F_e}{F_g} = 2.74 \times 10^{12}$

Part b)

$q = 3.37 \times 10^{-4} C$

Explanation:

As we know that electric force on electric charge is given as

$F = qE$

here we have

$q = 1.6 \times 10^{-19}C$

E = 153 N/C

now force is given as

$F = (1.6 \times 10^{-19})(153) = 2.45 \times 10^{-17} N$

Gravitational force on electric charge near surface of earth is given as

$F_g = mg$

$F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N$

now the ratio of two forces is given as

$\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}$

$\frac{F_e}{F_g} = 2.74 \times 10^{12}$

Part b)

Now the ball is balanced by the electric force and the force of gravity on it

so here we have

$F_g = qE$

$mg = qE$

$(5.25 \times 10^{-3})(9.81) = q(153)$

here we have

$q = 3.37 \times 10^{-4} C$

8 0

3 years ago

The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag

CaHeK987 [17]

The speed of tsunami is a.0.32 km.

Steps involved :

The equation s = 356d models the maximum speed that a tsunami can move at. It reads as follows: s = 200 km/h d =?

Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32

As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.

To learn more about tsunami refer : brainly.com/question/11687903

#SPJ4

6 0

2 years ago

A ball is dropped from the ceiling and free falls to the floor. Which one of the

Alex73 [517]

Answer:

Explanation:

Gravity

5 0

3 years ago

Choose the true statement concerning the mall or subatomic particles:

solniwko [45]

C is true, and just one of those has as much mass as about 1,840 electrons.

4 0

3 years ago

Read 2 more answers

Find the GCF 12, 18, and 84

ahrayia [7]

To find the answer, plot down the factors for every number.

12: 1, 2 ,3 ,4, 6, 12

18: 1, 2, 3, 6, 9, 18

84: 1, 2, 3, 4, 6, 7, 12

If you noticed, the number that was common to the 3 numbers, were 1, 2, 3, and 6
And 6 is the bigger number
So 6 is your GCF

5 0

3 years ago

Read 2 more answers