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3 years ago

A sound wave in the air has a frequency of 256 hertz and is traveling at a speed of 331 meters/second. What is its wavelength?

Physics

2 answers:

nikdorinn [45]3 years ago

6 0

2.39 is the answer cuh

emmainna [20.7K]3 years ago

6 0

Answer: The correct answer is 1.29 m/s.

Explanation:

The expression for the velocity of the wave is as follows;

$v=f\lambda$

Here, f is the frequency of the wave, v is the velocity of the wave and $\lambda$ is the wavelength of the wave.

It is given in the problem that a sound wave in the air has a frequency of 256 hertz and is traveling at a speed of 331 meters/second.

Calculate the wavelength of the wave by rearranging the above expression.

Put v= 331 m/s and f= 256 Hz by rearranging the above expression.

$\lambda =\frac{331}{256}$

$\lambda =1.29 m$

Therefore, the wavelength of the wave is 1.29.

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3 years ago

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Answer:

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3 years ago

What two units of measure are necessary for describing speed

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4 years ago

Define the types of friction and give FOUR examples of each

Verdich [7]

Answer:

Static Friction - acts on objects when they are resting on a surface

Sliding Friction - friction that acts on objects when they are sliding over a surface

Rolling Friction - friction that acts on objects when they are rolling over a surface

Fluid Friction - friction that acts on objects that are moving through a fluid

Explanation:

Examples of static include papers on a tabletop, towel hanging on a rack, bookmark in a book , car parked on a hill.

Example of sliding include sledding, pushing an object across a surface, rubbing one's hands together, a car sliding on ice.

Examples of rolling include truck tires, ball bearings, bike wheels, and car tires.

Examples of fluid include water pushing against a swimmer's body as they move through it , the movement of your coffee as you stir it with a spoon, sucking water through a straw, submarine moving through water.

4 0

3 years ago

An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below

grin007 [14]

<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let $P$ be the pressure at a point.

Let $p$ be the density fluid at a point.

Let $v$ be the velocity of fluid at a point.

Bernoulli's equation states that $P+\frac{1}{2}pv^{2}+pgh=constant$ for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let $p_{up}$ be the pressure of a point just above the wing.

Let $p_{do}$ be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

$\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}$

So, $p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa$

Force is given by the product of pressure difference and area.

Given that area is $27ms^{2}$ .

So,lifting force is $16398.48\times 27=442758.96N$

6 0

4 years ago