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2 years ago

A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3 m/s2?

Physics

1 answer:

Ann [662]2 years ago

7 0

Hello!

A 10 kg bowling ball would require. What force to accelerate down an alleyway at a rate of 3 m/s² ?

We have the following data:

F (force) = ? (in N or kg.m/s²)

m (mass) = 10 kg

a (acceleration) = 3 m/s²

We apply the data to the Net force formula, we have:

$F =m*a$

$F = 10\:kg * 3\:\dfrac{m}{s^2}$

$F = 30\:kg*\dfrac{m}{s^2} \to \boxed{\boxed{F = 30\:N}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

The force is 30 Newton

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If Star A is magnitude 1.0 and Star B is magnitude 9.6 , which is brighter and by what factor?

ludmilkaskok [199]

Answer:

Star A is brighter than Star B by a factor of 2754.22

Explanation:

Lets assume,

the magnitude of star A = m₁ = 1

the magnitude of star B = m₂ = 9.6

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Then, relation between the difference of magnitudes and apparent brightness of two stars are related as give below: $(m_{2} - m_{1}) = 2.5\log_{10}(b_{1}/b_{2})$

The current magnitude scale followed was formalized by Sir Norman Pogson in 1856. On this scale a magnitude 1 star is 2.512 times brighter than magnitude 2 star. A magnitude 2 star is 2.512 time brighter than a magnitude 3 star. That means a magnitude 1 star is (2.512x2.512) brighter than magnitude 3 bright star.

We need to find the factor by which star A is brighter than star B. Using the equation given above,

$(9.6 - 1) = 2.5\log_{10}(b_{1}/b_{2})$

$\frac{8.6}{2.5} = \log_{10}(b_{1}/b_{2})$

$\log_{10}(b_{1}/b_{2}) = 3.44$

Thus,

$(b_{1}/b_{2}) = 2754.22$

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2 years ago

Is condensation adding thermal energy

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2 years ago

A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. What is the magnitude and direction of the

Nuetrik [128]

Answer: A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. Then the magnitude and direction of the student's total displacement will be 87.32 m along the direction of AD or in east-south direction.

Explanation: To find the correct answer, we need to know about the Displacement of a body in motion.

<h3>What is displacement of a body in motion?</h3>

The displacement is the shortest distance between initial and final positions of a body.
It's a vector quantity, and can positive, negative, or zero.
The magnitude of displacement is less than or equal to the distance travelled.

<h3>How to solve the problem?</h3>

At first, we can draw a diagram showing the motion of the body.
From the diagram, the displacement of the body will be equal to the distance between point A and D.
To solve this, we can use Pythagoras theorem.

$AD=AC+CD\\AC^{2} =50^{2} +11^2\\AC=51.19 m\\Similarly,\\CD^2=35^2+9^2\\CD=36.13 m\\thus, \\AD=51.19+36.13=87.32 m$

Thus, from the above calculations, we can conclude that, the displacement of the body will be equal to 87.32 m along the direction of AD or in east-south direction.

Learn more about the Displacement here:

brainly.com/question/28020108

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Answer:

The ball will have a kinetic energy of 0.615 Joules.

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The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)

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marusya05 [52]

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