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3 years ago

Main function of gametes?

Physics

1 answer:

vichka [17]3 years ago

3 0

Sexual reproduction. thats the answer i think

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What happens to the sound of a train whistle as a train approaches and passes you? why?

omeli [17]

This is called, The Doppler effect.

In short terms, when the trains is farther away the wavelength of the whistles sound are longer and more separate from each other, and more farther away from you, as it gets closer to you, the wavelengths start getting shorter and more louder the closer it gets to you. Basically the <span>wavelengths change because of the motion of the source.</span>

8 0

3 years ago

A 0.22 kg mass attached to a spring undergoes simple harmonic motion with a period of 0.45 s. what is the force constant of the

MArishka [77]

T = 2π × √ (m / k)

T period
m mass
k spring constant

solve for k

4 0

3 years ago

A cosmological redshift occurs because light waves coming from stars and galaxies become bluer as they travel away from us. True

alexandr1967 [171]

<span>When stars are moving away (red shift) the wavelength increases and thus the object looks more reddish (Because red color has longer wavelengths). As opposed to when the star is moving closer the wavelength contracts (blue shift) and the object appears slightly blue. So, the statement is False.</span>

5 0

3 years ago

When you drop a ball it accelerates downward at a rate of g. If you instead throw it downward, then its acceleration immediately

Sauron [17]

The acceleration of the ball is always g

Explanation:

An object is said to be in free fall if there is only the force of gravity acting on it. In such situation, therefore, the net force on the ball is

$F=mg$ (1)

where

m is the mass of the ball

$g=9.8 m/s^2$ is the acceleration of gravity, pointing downward

Applying Newton's second law,

$F=ma$ (2)

where a is the acceleration, and equating (1) and (2), we find the acceleration of an object in free fall:

$mg=ma\\a=g$

So, any object in free fall has always an acceleration of $g$ (downward), regardless of its initial velocity.

Therefore, in this problem, it doesn't matter what is the direction of the initial velocity of the ball: its acceleration, in fact, will be always equal to g.

Learn more about free fall:

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#LearnwithBrainly

4 0

4 years ago

A vertical spring with a spring constant of 420 N/m is mounted on the floor. From directly above the spring, which is unstrained

mixas84 [53]

Answer:

19.53 cm

Explanation:

The computation of the height is as follows:

Here we applied the conservation of the energy formula

As we know that

P.E of the block = P.E of the spring

m g h = ( 1 ÷ 2) k x^2

where

m = 0.15

g = 9.81

k = 420

x = 0.037

So now put the values to the above formula

(0.15) (9.81) (h) = 1 ÷2 × 420 × (0.037)^2

1.4715 (h) = 0.28749

h = 0.19537 m

= 19.53 cm

3 0

3 years ago