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3 years ago

Find the Domain and range of each relation. 1. Q= {(3,4), (-4,1), (2,5), (-4,1), (0,0)}

Mathematics

1 answer:

zimovet [89]3 years ago

7 0

Answer:

Step-by-step explanation:

domain is all ur x values.....

domain = { -4,0,2,3}....u only have to write them once if they repeat

range is all ur y values....

range = { 0,1,4,5}

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Answer:A runner ran 20 miles in 150 minutes. If she runs at that speed,. How long would it take her to run 6 miles? ... How fast is she running in miles per hour? ... experience in reasoning with equivalent ratios and unit rates from both sides of the ratio.

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4 years ago

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$

To convert billion to million you multiple by 1000

$P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year$

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3 years ago

8. A salesman bought a computer from a manufacturer. The salesman the sold the computer

PolarNik [594]

Answer:

117,000

Step-by-step explanation:

156000÷100x25

=39000

Then

156000-39000

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3 years ago

Please help fast<br> The graph shows the function f(x)

DedPeter [7]

Answer:

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Step-by-step explanation:

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We add -1+5=6 and divide this by 2-0=2.

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The y-values on average change 3 units for every 1 unit of the x-values.

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3 years ago

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seropon [69]

So 0.25 is essentially 25/100. Divide 25 from the top and bottom to get 1/4

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3 years ago

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