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Otrada [13]
3 years ago
13

A block with mass ma = 14.0 kg on a smooth horizontal surface is connected by a thin cord that passes over a pulley to a second

block with mass mb = 6.0 kg which hangs vertically.determine the magnitude of the acceleration of the system.
Physics
1 answer:
Drupady [299]3 years ago
7 0
<span>We can assume that the horizontal surface has no friction and the pulley is massless. We can use Newton's second law to set up an equation. F = Ma F is the net force M is the total mass of the system a is the acceleration a = F / M a = (mb)(g) / (ma + mb) a = (6.0 kg)(9.80 m/s^2) / (6.0 kg + 14.0 kg) a = 58.8 N / 20 kg a = 2.94 m/s^2 The magnitude of the acceleration of the system is 2.94 m/s^2</span>
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F_x = T_x - F_e = 0\\T_x = F_e = k*\frac{q^2}{r^2}

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8 0
3 years ago
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