The terminal speed of the marble is 0.588 m/s.
<h3>Calculation:</h3>
We know that,
F = mg ......(1)
where,
F = force
m = mass
g = acceleration due to gravity
Also,
v = F/k ......(2)
where,
v = terminal speed
k = proportionality constant
Substituting the value of F from equation (1) in equation (2)
v = mg/k .......(3)
Given,
m = 30 g = 0.030 kg
k = 0.500 kg/s
g = 9.8 m/s²
To find,
v =?
Put the values in equation (3)
v = mg/k
v = 0.03(9.8)/ 0.500
= 0.294/0.500
= 0.588 m/s
Hence, the terminal speed of the marble is 0.588 m/s.
Learn more about calculation of force here:
brainly.com/question/15562875
#SPJ4
.
Answer:
the release will be at 3.266 m distance
Explanation:
mass = 1 Kg
spring constant (k) = 800 N/m
initial compression = 0.20 m
θ = 30⁰



hence the release will be at 3.266 m distance.
B) the crust is much thinner from the other layers
Answer:
<em>The change in momentum of the car is 3575 Kg.m/s</em>
Explanation:
<u>Impulse and Momentum</u>
The impulse (J) experienced by the object equals the change in momentum of the object (Δp).
The formula that represents the above statement is:
J = Δp
The impulse is calculated as
J = F.t
Where F is the applied force and t is the time.
The car hits a wall with a force of F=6500 N and stops in 0.55 s. Thus, the impulse is:
J = 6500 * 0.55
J = 3575 Kg.m/s
The change in momentum of the car is:

The change in momentum of the car is 3575 Kg.m/s