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Morgarella [4.7K]
2 years ago
15

State all kinds of errors ​

Physics
1 answer:
JulijaS [17]2 years ago
4 0

Answer:

Instrumental error

Environmental error

Observational error

Theoritical error

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V125BC [204]
It's a combination of substances that does not have uniform composition and properties.
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3 years ago
A spring has a length of .200 m when a .300 kg hangs from it,and a length of .750 m when a 1.95 kg hangs from it.what is the for
musickatia [10]

1) 29.5 N/m

2) 0.100 m

Explanation:

1)

The force constant of the spring can be found by using the fact that the force on the spring is proportional to the extension of the spring (Hooke's Law). Therefore, we can write:

\Delta F= k \Delta x

where

\Delta F = F_2 - F_1 is the change in the force on the spring, where

F_1 = m_1 g = (0.300)(9.8)=2.94 N is the force applied when the hanging mass is

m_1 = 0.300 kg

F_2 = m_2 g = (1.95)(9.8)=19.1 N is the force applied when the hanging mass is

m_2 = 1.95 kg

\Delta x=x_2 -x_1 is the change in extension of the spring, where

x_1=0.200 m is the extension of the spring when the hanging mass is 0.300 kg

x_2=0.750 m is the extension of the spring when the hanging mass is 1.95 kg

Solving for k,

k=\frac{F_2-F_1}{x_2-x_1}=\frac{19.1-2.94}{0.750-0.200}=29.5 N/m

2)

When the first mass is hanging on the spring, we have

F_1 = k (x_1 - x_0)

where:

F_1 is the force applied on the spring (the weight of the hanging mass)

k is the spring constant

x_1 is the extension of the spring wrt its natural length

x_0 is the natural length of the spring (the unloaded length)

Here we have

F_1=2.94 N

k = 29.5 N/m

x_1=0.200 m

Solving for x_0, we find:

x_0 = x_1 - \frac{F_1}{k}=0.200 - \frac{2.94}{29.5}=0.100 m

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The answer would be 49. Check the attach file for solution.

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4 years ago
What formula gives the strength of an electric field, E, at a distance from a known source charge?
Deffense [45]
<h2>Hello!</h2>

The answer is: Coulomb's law equation.

<h2>Why?</h2>

The Coulomb's law states that the strength of an electric field (between two charges) can be calculated by multiplying their charges and dividing it into the square of the distance between their centers.

E=\frac{k*q*Q}{d^{2} }

Where:

E = Electric Field Strenght

k=9.0*10^{9}  \frac{N.m^{2} }{C^{2} }

q=TestCharge\\Q=SourceCharge\\

d = separation between charges (m)

Have a nice day!

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