Answer:
Explanation:
Let x₀ be the amplitude , ω be the angular velocity
velocity at displacement x ,
v = ω 
at 
v = ω [ 
v² = ω² x
1/2 m v²
= 3/8 m x ω²x₀²
Total energy = 1/2 m ω²x₀²
Kinetic energy as fraction of total energy
= 3/8 m x ω²x₀² x 2 / m ω²x₀²
= 3 / 4
Fraction of potential energy
= 1 - 3/4
1/4
c )
Half kinetic = half potential energy
= 1/4 m ω²x₀²
1/2 m ω²( x₀²- x ² )
x₀²/2 = x₀²- x ²
x² = x₀²/2
x = x₀/√2
Velocity
,
m/s2
<span> Speed has direction and velocity.</span>
Answer:
Heat required to melt 1 lb of ice is 151.469 KJ
Explanation:
We have given mass of ice = 1 lb
We know that 1 lb = 0.4535 kg
Latent heat of fusion for ice =334 KJ/kg
Amount if heat for fusion of ice is given by
, here m is mass of ice and L is latent heat of fusion
So heat 
So heat required to melt 1 lb of ice is equal to 151.469 KJ
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