work is done by the pulling force which is same as the tension force in the rope. the net work done is zero for the crate since crate moves at constant velocity. but there is work done by the tension force which is equal in magnitude to the work done by the frictional force.
T = tension force in the rope = 115 N
d = displacement of the crate = 7.0 m
θ = angle between the direction of tension force and displacement = 37 deg
work done on the crate is given as
W = F d Cosθ
inserting the values given above
W = (115) (7.0) Cos37
W = 643 J
-1.1m/s
Explanation:
Work out which of the displacement (S), initial velocity (U), acceleration (A) and time (T) you have to solve for final velocity (V). If you have U, A and T, use V = U + AT. If you have S, U and T, use V = 2(S/T) - U.
Answer:
cause of the g force pushing u back
Explanation:
In increases depends how you move the muscle
The weight of an object is given by:
where
F is the weight
m is the mass of the object
is the gravitational acceleration
The piece of ham in this problem has a mass of
m=630 g = 0.63 kg
therefore its weight is
