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Alinara [238K]
3 years ago
5

Reflect polygon P using line L

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

Just align it on the other side.

Step-by-step explanation:

Top right point, count how many units it is from the reflective line. Then count that many units on the other side and place the point. So on so forth.

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-845 degree coterminal angle
meriva
Check the picture below.

with negative angles, we go "clockwise", the same direction a clock hands move.

so -360-360-125 = -845.

so as you see in the picture, you go around twice, and then a little bit more, an extra 125°, landing you at -125°, or its positive counterpart, 235°.

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3 years ago
PLEASE HELP I WILL NAME YOU THE BRAINIEST
tino4ka555 [31]
2 x 1/6 = 2/6 which can be reduced to 1/3
4 x 3/8 = 1 and 4/8 which can again be reduced to 1 and 1/2

problem 2 - 3/4

problem 3 - 2 (whole number)
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2 years ago
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Find three things in a kitchen that you can measure the time of in minutes
Leviafan [203]
Microwave, oven, coffee maker
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Some people advise that in very cold​ weather, you should keep the gas tank in your car more than half full. Lou​'s car had 6.8
Katen [24]

Answer: You have the following information given in the problem above:

- Lou filled the tank with gas that cost ​$3.80 per gallon.

-   Lou​'s car had 5.9 gallons in the 13​-gallon tank.

2. Therefore, if he filled the tank, you can calculate the total amount of money Lou spent, by subtracting 13 gallons and 5.9 gallons and multiplying the result by ​$3.80.

3. Then, the result is:

$26.98

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The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi
Elan Coil [88]

Answer:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150  

Weight after diet 170 130 215 152

We define the random variable D = before-after and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

And the deviation with:

s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And after replace we got:

\bar D= 7, s_d = 13.638

And the confidence interval for this case would be given by:

\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1= 4-1=3

For the 95% of confidence the value for the significance is \alpha=0.05 and the critical value would be t_{\alpha/2}= 3.182. And replacing we got:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

6 0
3 years ago
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