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shtirl [24]
4 years ago
12

For each of the following functions f(x) below : Find its limits limx→±[infinity]f(x) as x approachs ±[infinity] . Choose the va

lues of x where f(x) is differentiable, i.e. f′(x) exists Choose the values of x where f(x) is also strictly increasing, i.e. f′(x)>0 . For f(x)=max(0,x) : (If the limit diverges to infty, enter inf for [infinity], and -inf for −[infinity] ) limx→−[infinity]f(x)=
Mathematics
1 answer:
kicyunya [14]4 years ago
6 0

Answer:

See below

Step-by-step explanation:

f(x)=\max\{0,x\} then f(x)=0 if x<0 and f(x)=x if x≥0.

When x→-∞, f is the constant function zero, therefore \lim_{n\rightarrow -\infty}f(x)=0. When x→∞, f(x)=x and x grows indefinitely. Thus \lim_{n\rightarrow \infty}f(x)=\infty

f is differentiable if x≠0. If x>0, f'(x)=1 (the derivative of f(x)=x) and if x<0, f'(0)=0 (the derivative of the constant zero). In x=0, the right-hand derivative is 1, but the left-hand derivative is 0, hence f'(0) does not exist,

f'(x)>0 for all x>0. Therefore f(x) is strictly increasing on the inverval (0,∞).

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What number goes in the box in the followng sequence 5 11 23 ? 95 191​
Alina [70]

Answer:

47

Step-by-step explanation:

The number that should go after 23 is 47.

The pattern seems to be (n * 2) + 1, where n is the value of the previous number.

We start with the number 5:

5

(5 * 2) + 1  = 11

11

(11 * 2) + 1 = 23

23

(23 * 2) + 1 = 47

47

... and so on

The pattern should continue as follows.

Hope this helps!

3 0
3 years ago
G(x)=-4+7 rate of change
Ratling [72]
What exactly are you trying to find but I tried to do the problem and I got 3
6 0
3 years ago
77. the volume of a cube is increasing at a rate of <img src="https://tex.z-dn.net/?f=10%20%5Cmathrm%7B~cm%7D%5E%7B3%7D%20%2F%20
Colt1911 [192]

Answer:

\displaystyle \frac{4}{3}\text{cm}^2/\text{min}

Step-by-step explanation:

<u>Given</u>

<u />\displaystyle \frac{dV}{dt}=10\:\text{cm}^3/\text{min}\\ \\V=s^3\\\\SA=6s^2\\\\\frac{d(SA)}{dt}=?}\:;s=30\text{cm}

<u>Solution</u>

(1) Find the rate of the cube's edge length with respect to time at s=30:

\displaystyle V=s^3\\\\\frac{dV}{dt}=3s^2\frac{ds}{dt}\\ \\10=3(30)^2\frac{ds}{dt}\\ \\10=3(900)\frac{ds}{dt}\\\\10=2700\frac{ds}{dt}\\\\\frac{10}{2700}=\frac{ds}{dt}\\\\\frac{ds}{dt}=\frac{1}{270}\text{cm}/\text{min}

(2) Find the rate of the cube's surface area with respect to time at s=30:

\displaystyle SA=6s^2\\\\\frac{d(SA)}{dt}=12s\frac{ds}{dt}\\ \\\frac{d(SA)}{dt}=12(30)\biggr(\frac{1}{270}\biggr)\\\\\frac{d(SA)}{dt}=\frac{360}{270}\biggr\\\\\frac{d(SA)}{dt}=\frac{4}{3}\text{cm}^2/\text{min}

Therefore, the surface area increases when the length of an edge is 30 cm at a rate of \displaystyle \frac{4}{3}\text{cm}^2/\text{min}.

6 0
2 years ago
Identify the equation that represents the data in the table
ella [17]

Answer:

i would say A

Step-by-step explanation:

6 0
3 years ago
The information above describes the real GDP per capita for a country for the period from 1985 through to 2001. If a new busines
topjm [15]

Answer:

The question is incomplete, here is the complete question.

Year                               Real GDP per Capita

1985                                          6,000

1986                                          6,300

1987                                           6,700

1988                                           7,200

1989                                           7,850

1990                                           8,250

1991                                            8,450

1992                                           8,550

1993                                           8,575

1994                                           8,510

1995                                           8,370

1996                                           8,100

1997                                            7,950

1998                                           7,925

1999                                           7,960

2000                                          8,035

2001                                            8,155

The information above describes the real GDP per capita for a country for the period from 1985 through to 2001. If a new business cycle began in 1985, how long was this cycle? In which year did the peak occur? The trough occurred in which year? How long was the expansion? How long was the recession?

Step-by-step explanation:

a.If a new business cycle began in 1985, how long was this cycle?

The business cycle describes the rise and fall in production output of goods and services in an economy. In the data given above, a business cycle is complete in the year 1998. If the cycle started in 1985 then it was 14 years long.

b. In which year did the peak occur? The trough occurred in which year?

In the data given above, the peak occured in year 1993 (GDP per capita of 8,575) and trough occurred in the year 1998 (GDP per capita of 7,925).

c. How long was the expansion? How long was the recession?

Expansion was 9 years long (1985-1993) and recession was of 5 years (1994-1998).

7 0
3 years ago
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