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shtirl [24]
3 years ago
12

For each of the following functions f(x) below : Find its limits limx→±[infinity]f(x) as x approachs ±[infinity] . Choose the va

lues of x where f(x) is differentiable, i.e. f′(x) exists Choose the values of x where f(x) is also strictly increasing, i.e. f′(x)>0 . For f(x)=max(0,x) : (If the limit diverges to infty, enter inf for [infinity], and -inf for −[infinity] ) limx→−[infinity]f(x)=
Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

See below

Step-by-step explanation:

f(x)=\max\{0,x\} then f(x)=0 if x<0 and f(x)=x if x≥0.

When x→-∞, f is the constant function zero, therefore \lim_{n\rightarrow -\infty}f(x)=0. When x→∞, f(x)=x and x grows indefinitely. Thus \lim_{n\rightarrow \infty}f(x)=\infty

f is differentiable if x≠0. If x>0, f'(x)=1 (the derivative of f(x)=x) and if x<0, f'(0)=0 (the derivative of the constant zero). In x=0, the right-hand derivative is 1, but the left-hand derivative is 0, hence f'(0) does not exist,

f'(x)>0 for all x>0. Therefore f(x) is strictly increasing on the inverval (0,∞).

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How many chords are determined by joining dots on a circle
Aleonysh [2.5K]

Answer:The calculation is that from each of the point a chord can be connected to the 7 other points… and that makes 56 chords.

Step-by-step explanation:

3 0
2 years ago
Help me please I’m not good at math
Deffense [45]

Answer:

i think the answer is 7/4

6 0
3 years ago
Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10
damaskus [11]

Answer:

4

Step-by-step explanation:

set

f(x,y)=x+y\\

constrain:

g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10

Partial derivatives:

f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2

Lagrange multiplier:

grad(f)=a*grad(g)+b*grad(h)\\

\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]

4 equations:

1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10

By solving:

a=4/9\\b=-2/27\\x+y=4

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4

The maximum is 4

6 0
3 years ago
One smartphone plan costs $52 per month for talk and messaging and $8 per gigabyte of data used each month. A second smartphone
valina [46]

Answer:

Both plans would cost $100 if 6 gigabytes of data are used.

Explanation:

From the question, the system of equation are correctly represented by using small letter c to represent the total cost in dollars for both equations as already assumed in the question as follows:

c = 52 + 8d ........................... (1)

c = 82 + 3d ........................... (2)

Since c is common to both, equations (1) and (2) can therefore be equated and d solved for as follows:

52 + 8d = 82 + 3d

8d - 3d = 82 - 52

5d = 30

d = 30 / 5

d = 6

Substituting d = 6 into equation (1), we have:

c = 52 + (8 * 6)

c = 52 + 48

c = 100

Since d = 6 and c = 100, it therefore implies that both plans would cost $100 if 6 gigabytes of data are used.

5 0
2 years ago
Mrs Lim packs 35 big and small bags of candies for her pupils. Each big bag contains 12 candies and each small bag contains 7 ca
Anastasy [175]

Answer:

there are 11 big-bags and 24 small-bags.

Step-by-step explanation:

there are x big-bags and y small-bags.

so now we can know:

(1) x + y = 35

(2) 12x + 7y = 300

in (1),we can do like this:

both left and right x7

then (x + y)x7 = 35 x 7

then 7x + 7y = 35 x 7  

then 7x + 7y = 245

now,

(1)7x + 7y =245

(2)12x + 7y = 300

we can both left and right do this: (2) - (1)

then

(12x + 7y) - (7x + 7y) = 300 -245

then

12x + 7y - 7x - 7y = 300 -245

then

12x - 7x +7y - 7y =300 -245

then

5x =55

then

5x ÷ 5 = 55 ÷ 5

then

x = 11

because

x + y =35;x=11

so

11 + y =35

11+ y -11 = 35 -11

then

y = 24

now we know:there are 11 big-bags and 24 small-bags.

3 0
3 years ago
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