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shtirl [24]
3 years ago
12

For each of the following functions f(x) below : Find its limits limx→±[infinity]f(x) as x approachs ±[infinity] . Choose the va

lues of x where f(x) is differentiable, i.e. f′(x) exists Choose the values of x where f(x) is also strictly increasing, i.e. f′(x)>0 . For f(x)=max(0,x) : (If the limit diverges to infty, enter inf for [infinity], and -inf for −[infinity] ) limx→−[infinity]f(x)=
Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

See below

Step-by-step explanation:

f(x)=\max\{0,x\} then f(x)=0 if x<0 and f(x)=x if x≥0.

When x→-∞, f is the constant function zero, therefore \lim_{n\rightarrow -\infty}f(x)=0. When x→∞, f(x)=x and x grows indefinitely. Thus \lim_{n\rightarrow \infty}f(x)=\infty

f is differentiable if x≠0. If x>0, f'(x)=1 (the derivative of f(x)=x) and if x<0, f'(0)=0 (the derivative of the constant zero). In x=0, the right-hand derivative is 1, but the left-hand derivative is 0, hence f'(0) does not exist,

f'(x)>0 for all x>0. Therefore f(x) is strictly increasing on the inverval (0,∞).

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Answer:

h = 12

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Step-by-step explanation:

Given

The attached triangle

Required

Find h, x and y

Let the base of the triangle be 15.

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So, the area is:

A = \frac{1}{2}  * 25 * h

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A = \frac{1}{2}  * 25h

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\frac{1}{2}*25h = 150

Solve for h

h = \frac{150 *2}{25}

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Considering the smallest triangle

Hypotenuse = 15

So:

15^2 = h^2 + x^2

15^2 = 12^2 + x^2

This gives:

15^2 - 12^2 = x^2

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Solving for y

x + y = 25

y= 25 - x

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y= 16

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