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4 years ago

Average velocity is different than average speed because calculating average velocity involves what?

2 answers:

8 0

Two things that aren't involved in speed: -- the straight-line distance between the start- and end- points. -- the direction from start-point to end-point.

Leona [35]4 years ago

5 0

The correct answer to the question is: Direction

EXPLANATION:

The average velocity of a body is defined as the rate of change of displacement.

We know that displacement is a vector quantity. Hence, it has magnitude as well as direction for its specification.

On the other hand, the average speed of a body is defined as the rate of change of distance travelled. Hence, the average speed of a body is a scalar quantity. It means that it has only magnitude.

Hence, during the calculation of average velocity,we have to think of its direction.

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Show your work please

nekit [7.7K]

Answer:

$V = U + at$

Explanation:

<u>Given the following data;</u>

Initial velocity = 0 (since the stone is starting from rest).

Final velocity = 32 m/s

Acceleration = g = 10 m/s²

Time = 3.2 seconds

To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;

$V = U + at$

Where;

V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.

Substituting into the formula, we have;

$32 = 0 + 10*3.2$

$32 = 0 + 32$

$32 = 32$

<em>Proven: 32 m/s = 32 m/s</em>

7 0

3 years ago

A helium balloon has a radius of 2m. The density of helium of helium is 0.17 kg/m3 and the density of air is 1.25 kg/m3. What is

3241004551 [841]

To solve this problem we will begin by finding the force on each of the elements. For this it will be necessary to obtain the mass, which can be related to density and volume. Finally, by balancing forces it will be possible to obtain the final value of the maximum mass that can be lifted.

By Newton's second law we have,

$F = mg$

Here,

g = Gravitational acceleration

m = mass

At the same time mass can be described as,

$m_1 = \rho \times V$

$m_1 = (1.25)\times \frac{4}{3} (2)^2$

Therefore the Force 1 is,

$F = m_1 g$

$F = \frac{40\pi }{3} (9.8)$

$F = 410.501N$

Applying the same concepto but for the second mass we have,

$m_2 = \rho \times V$

$m_2 = (0.17) \times \frac{3}{4} \pi 2^2$

$m_2 = 5.697kg$

Now by equilibrium we have,

$W + mg = F$

$m = \frac{F+W}{g}$

$m = \frac{410.501-55.828}{9.8}$

$m = 36.19kg$

Therefore the maximum mass lift by balloon is $36.19kg$

3 0

3 years ago

In atomic bombs, a relatively small amount of matter (uranium atoms) is converted to a relatively huge amount of energy (the bla

viva [34]

Explanation:

In atomic bombs, nuclear reactions is at work.

Depending on the reaction, matter is converted to energy either by nuclear fusion or fission process.

Nuclear reactions takes place in the nucleus of elements.
Inside the nucleus, the bulk of the mass of atoms are concentrated via by the presence of protons and neutrons.
These particles called nucleons typifies the mass of an atom.
When nuclear reactions occur, they take place in the nucleus of atoms.
This interaction leads to the conversion of some of these masses to energy.
As predicted by the Einstein's equation, E = mc², mass m and energy E are both equivalent.
c is the speed of light.
Instead of converting all the mass to product, some are transformed into energy.
The mass and energy equivalence typifies nuclear reactions.
There is always a mass deficit that accompanies such reactions.

learn more:

Nuclear reactions brainly.com/question/10094982

#learnwithBrainly

8 0

3 years ago

A 3.00-kg block starts from rest at the top of a 33.0° incline and slides 2.00 m down the incline in 1.80 s. (a) Find the accele

ElenaW [278]

(a) $1.23 m/s^2$

Let's analyze the motion along the direction of the incline. We have:

- distance covered: d = 2.00 m

- time taken: t = 1.80 s

- initial velocity: u = 0

- acceleration: a

We can use the following SUVAT equation:

$d = ut + \frac{1}{2}at^2$

Since u=0 (the block starts from rest), it becomes

$d=\frac{1}{2}at^2$

So by solving the equation for a, we find the acceleration:

$a=\frac{2d}{t^2}=\frac{2(2.00 m)}{(1.80 s)^2}=1.23 m/s^2$

(b) 0.50

There are two forces acting on the block along the direction of the incline:

- The component of the weight parallel to the surface of the incline:

$W_p = mg sin \theta$

where

m = 3.00 kg is the mass of the block

g = 9.8 m/s^2 is the acceleration due to gravity

$\theta=33.0^{\circ}$ is the angle of the incline

This force is directed down along the slope

- The frictional force, given by

$F_f = - \mu mg cos \theta$

where

$\mu$ is the coefficient of kinetic friction

According to Newton's second law, the resultant of the forces is equal to the product between mass and acceleration:

$W-F_f = ma\\mg sin \theta - \mu mg cos \theta = ma$

Solving for $\mu$ , we find

$\mu = \frac{g sin \theta - a}{g cos \theta}=\frac{(9.8 m/s^2)sin 33.0^{\circ} - 1.23 m/s^2}{(9.8 m/s^2) cos 33.0^{\circ}}=0.50$

(c) 12.3 N

The frictional force acting on the block is given by

$F_f = \mu mg cos \theta$

where

$\mu = 0.50$ is the coefficient of kinetic friction

m = 3.00 kg is the mass of the block

g = 9.8 m/s^2 is the acceleration of gravity

$\theta=33.0^{\circ}$ is the angle of the incline

Substituting, we find

$F_f = (0.50)(3.00 kg)(9.8 m/s^2) cos 33.0^{\circ} =12.3 N$

(d) 6.26 m/s

The motion along the surface of the incline is an accelerated motion, so we can use the following SUVAT equation

$v^2 - u^2 = 2ad$

where

v is the final speed of the block

u = 0 is the initial speed

a = 1.23 m/s^2 is the acceleration

d = 2.00 m is the distance covered

Solving the equation for v, we find the speed of the block after 2.00 m:

$v=\sqrt{u^2 + 2ad}=\sqrt{0^2+2(9.8 m/s^2)(2.00 m)}=6.26 m/s$

5 0

3 years ago

Light initially traveling in air n=1 is incident on a flat plane of glass n=1.6 at an angle of 20 degrees to the normal. find an

Black_prince [1.1K]

Answer:

The reflected angle is 20 °.

The angle of refraction = 12.34°.

Explanation:

For reflection,

Angle of incidence = Angle of the reflection.

Thus,

Given that the angle of incidence is 20 °

So, the reflected angle is 20°.

For refraction,

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index of water which is 1

n₂ is the refractive index of water which is 1.6

So,

$\frac {sin\theta_2}{sin20}=\frac {1}{1.6}$

${sin\theta_2}=0.2138$

Angle of refraction = sin⁻¹ 0.56 = 12.34°.

7 0

4 years ago