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Ivahew [28]
4 years ago
7

Average velocity is different than average speed because calculating average velocity involves what?

Physics
2 answers:
Dominik [7]4 years ago
8 0
Two things that aren't involved in speed: -- the straight-line distance between the start- and end- points. -- the direction from start-point to end-point.
Leona [35]4 years ago
5 0

The correct answer to the question is: Direction

EXPLANATION:

The average velocity of a body is defined as the rate of change of displacement.

We know that displacement is a vector quantity. Hence, it has magnitude as well as direction for its specification.

On the other hand, the average speed of a body is defined as the rate of change of distance travelled. Hence, the average speed of a body is a scalar quantity. It means that it has only magnitude.

Hence, during the calculation of average velocity,we have to think of its direction.

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In a cyclotron, the orbital radius of protons with energy 300 keV is 16.0 cm . You are redesigning the cyclotron to be used inst
Archy [21]

Answer:

16 cm

Explanation:

For protons:

Energy, E = 300 keV

radius of orbit, r1 = 16 cm

the relation for the energy and velocity is given by

E = \frac{1}{2}mv^{2}

So, v = \sqrt{\frac{2E}{m}}   .... (1)

Now,

r = \frac{mv}{Bq}

Substitute the value of v from equation (1), we get

r = \frac{\sqrt{2mE}}{Bq}

Let the radius of the alpha particle is r2.

For proton

So, r_{1} = \frac{\sqrt{2m_{1}E}}{Bq_{1}}    ... (2)

Where, m1 is the mass of proton, q1 is the charge of proton

For alpha particle

So, r_{2} = \frac{\sqrt{2m_{2}E}}{Bq_{2}}    ... (3)

Where, m2 is the mass of alpha particle, q2 is the charge of alpha particle

Divide equation (2) by equation (3), we get

\frac{r_{1}}{r_{2}}=\frac{q_{2}}{q_{1}}\times \sqrt{\frac{m_{1}}{m_{2}}}

q1 = q

q2 = 2q

m1 = m

m2 = 4m

By substituting the values

\frac{r_{1}}{r_{2}}=\frac{2q}}{q}}\times \sqrt{\frac{m}}{4m}}=1

So, r2 = r1 = 16 cm

Thus, the radius of the alpha particle is 16 cm.

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