Explanation:
s = ut + 1/2 a t^2
200 = 0 * 6 + 1/2 * a * (6)^2
200 = 1/2 * a * 36
200 = 18 a
a = 200/18
a= 11.1m/sec^2
v = u + at
v = 0 + 11.1 * 6
v = 66.6m/s
hope it helps you
To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,
Q = V*A
Where,
A= Cross-sectional Area
V = Velocity
The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,
Our values are given as,
Re-arrange the equation to find the first ratio of rates we have:
The second ratio of rates is
The time for the car to drive directly south is determined as 7.15 s.
<h3>Time for the car to drive directly west</h3>
The time for the car to drive directly south is determined by applying the concept of slope.
slope = Δy/Δx
a = Δv/Δt
Δt = Δv/a
Δt = (26.8)/(3.75)
Δt = 7.15 s
Thus, the time for the car to drive directly south is determined as 7.15 s.
Learn more about acceleration here: brainly.com/question/605631
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I just figured this out now.
First you would use the formula
Ephoton= hc/λ and substitute in the value's of plank's constant, the speed of light in a vaccum and the wavelength which will give you the energy in joules. Then you go to the reference table and solve for the energy used between the different levels for Mercury making sure to convert electron volts to jules. In the end the correct answer should be energy level D.
