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KonstantinChe [14]
3 years ago
15

A bow accelerates a 100g arrow at 50m/s calculate the force acting on the arrow in Newton’s

Physics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

Explanation:

Newton's law states that F=mg, or in other applications F=ma, where:

F= force acting on the system  

m= mass of the system and

a= acceleration (or g= gravitational acceleration which is 9.8m/s^2)

In your question we know the following variables:

The mass of the arrow (m= 100g, however we should use kilograms- 0.1kg)

The acceleration of the arrow (a=50m/s^2)

If we substitute these values into our given equation, we can find the force acting on the arrow.

F = m x a

F= (0.1) x (50)

F = 5N

hope this helps :)

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Two shuffleboard disks of equal mass, one orange and the other yellow, are involved in an elastic, glancing collision. The yello
klemol [59]

Answer:

3.62m/s and 2.83m/s

Explanation:

Apply conservation of momentum

For vertical component,

Pfy = Piy

m* Vof (sin38) - m*Vgf (sin52) = 0

Divide through by m

Vof(sin38) - Vgf(sin52) = 0

Vof(sin38) = Vgf(sin52)

Vof (sin38/sin52) = Vgf

0.7813Vof = Vgf

For horizontal component

Pxf= Pxi

m* Vof (cos38) - m*Vgf (cos52) = m*4.6

Divide through by m

Vof(cos38) + Vgf(cos52) = 4.6

Recall that

0.7813Vof = Vgf

Vof(cos38) + 0.7813 Vof(cos52) = 4.6

0.7880Vof + 0.4810Vof = 4.

1.269Vof = 4.6

Vof = 4.6/1.269

Vof = 3.62m/s

Recall that

0.7813Vof = Vgf

Vgf = 0.7813 * 3.62

Vgf = 2.83m/s

3 0
3 years ago
A ___________ is how strong the push or pull is
KatRina [158]
The answer is force
4 0
3 years ago
A 8.34 × 103-kg lunar landing craft is about to touch down on the surface of the moon, where the acceleration due to gravity is
Mnenie [13.5K]

Answer:

21870.3156 N

Explanation:

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 1.6 m/s²

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-18.2^2}{2\times 162}\\\Rightarrow a=-1.02234\ m/s^2

The acceleration of the craft should be 1.02234 m/s²

F=ma\\\Rightarrow F=8.34\times 10^3\times 1.02234\\\Rightarrow F=8526.3156\ N

Weight of the craft

W=mg\\\Rightarrow W=8.34\times 10^3\times 1.6\\\Rightarrow W=13344\ N

Thrust

F_t=F+W\\\Rightarrow F_t=8526.3156+13344\\\Rightarrow F_t=21870.3156\ N

The thrust needed to reduce the velocity to zero at the instant when the craft touches the lunar surface is 21870.3156 N

3 0
3 years ago
What is the most important source of water vapor in the atmosphere?
guapka [62]
The answer is Oceans.  It is the most important source of water vapor in the atmosphere.  <span>Given the huge amount of water they have and their huge surface areas, naturally the bulk of water which evaporates and enters the atmosphere is from oceans.</span>
8 0
3 years ago
The loudness of a sound is the waves amplitude <br><br><br><br> True or false
kakasveta [241]

Answer:

true i think

Explanation:

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4 0
2 years ago
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