Answer:
T = 2.4 + 2.4 = 4.8 [s]
Explanation:
In order to solve this problem, we must use the following kinematics equation and calculate the acceleration value.
Vo = inital velocity = 0
x - xo = 15 [m]
t = time = 2.4 [s]
15 = 0.5*a*(2.4)^2
a = 5.208 [m/s^2]
We can use the same equation to find the time.
30 = 15 + 0.5*(5.208)*t^2
t = 2.4 [s]
T = 2.4 + 2.4 = 4.8 [s]
The answer is d because you have to make sure that everything is right
Sunshine will help prode vitamin C
A :-) for this question , we should apply
F = ma
( i ) Given - m = 2 kg
a = 15 m/s^2
Solution :
F = ma
F = 2 x 15
F = 30 N
( ii ) Given - m = 2 kg
a = 10 m/s^2
Solution :
F = ma
F = 2 x 10
F = 20 N
.:. The net force of object ( i ) has greater force compared to object ( ii ) by
( 30 - 20 ) 10 N
First, you find the velocity at each component. The general equation is:
a = (v2 - v1)/t
a,x = (v2,x - v1,x)/t
-0.105 = (v2,x - 8.57)/6.67
v2,x = 7.87 m/s
a,y = (v2,y - v1,y)/t
0.101 = (v2,y - -2.61)/6.67
v2,y = -1.94 m/s
To find the final speed, find the resultant velocity by taking the hypotenuse.
v^2 = (v2,x)^2 + (v2,y)^2
v^2 = (7.87)^2 + (-1.94)^2
v = 8.1 m/s
