Answer:
At height of 45 meter from the ground two stones will meet each other.
Explanation:
Let the height covered by the stone thrown up be x.
And time at which both will meet be t
A stone is dropped from height of 50 m on earth.
Distance from where the stone is dropped to point where it meets another stone= (50 -x) m
Initial velocity of the stone = u = 0 m/s
Acceleration due to gravity = g =
(Second equation of motion)
..(1)
A stone is tossed upward the ground .
Height of stone in 3.16 s = x
Initial velocity of the stone = u' = 50 m/s
Acceleration due to gravity = -g =
(Second equation of motion)
...(2)
From (1) and (2)
t = 1 sec, x = 45 m
At height of 45 meter from the ground two stones will meet each other.