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3 years ago

A 2.73 kg cylindrical grinding wheel with a radius of 31 cm rotates at 1416 rpm. What is its angular momentum? Answers:

Physics

1 answer:

Nezavi [6.7K]3 years ago

5 0

Answer:

The angular momentum of the wheel is $19.45\ kg-m^2/s$ .

Explanation:

It is given that,

Mass of the wheel, m = 2.73 kg

Radius of the wheel, r = 31 cm = 0.31 m

Angular speed of the wheel, $\omega=1416\ rpm= 148.28\ rad/s$

We need to find its angular momentum. It is given by :

$L=I\omega$

I is the moment of inertia of the wheel, $I=\dfrac{mr^2}{2}$

$L=\dfrac{mr^2}{2}\times \omega$

$L=\dfrac{2.73\times (0.31)^2}{2}\times 148.28$

$L = 19.45\ kg-m^2/s$

So, the angular momentum of the wheel is $19.45\ kg-m^2/s$ . Hence, this is the required solution.

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A policeman starts giving chase 60 seconds after a stolen car zooms by at 108 km/hr. At what minimum speed should he drive if he

Iteru [2.4K]

Answer:

30.93 m/s

Explanation:

Given that, the speed of stolen car is,

$v_{s} =108km/hr\\v_{s} =108\times \frac{5}{18}m/s\\ v_{s} =30m/s$

As policeman start chasing the stolen car after 60 seconds.

Now suppose the speed of policeman car is, $v_{p}$

The policeman catches the stolen car at a distance of,

$S=60km\\S=60000m$

Now the distance covered by the policeman in time t is $v_{p}\times t$

And the distane cover by the thief in stolen car in time(t+60s) is $v_{s}\times (t+60sec)$ .

And these distances are equal and they are equal to 60000 m.

Therefore,

$v_{p}\times t=v_{s}\times (t+60sec)=60000m$

Therfore,

$v_{s}\times (t+60sec)=60000m\\30m/s\times (t+60sec)=60000m\\(t+60s)=2000s\\t=1940s$

Now use this value to solve for minimum speed of policeman's car.

$v_{p}\times 1940=60000\\v_{p}=30.93 m/s$

Therefore minimum speed of policeman's car is 30.93 m/s.

6 0

3 years ago

A car has an initial velocity of 11.2 m /sec. the car accelerates at 10.0 m /s2 for 8.0 seconds. what is the velocity of the car

Vinil7 [7]

Initial velocity(u) = 11.2 m/s.
Final velocity(v) = ?
acceleration(a) = 10.2 m/s²

Using kinematic equation v = u + at

v = 11.2 + 10 x 8 = 11.2 + 80 = 91.2 m/s.

Therefore final velocity is 91.2 m/s.

7 0

3 years ago

Convert an acceleration of 12m/s^2 to km/h^2

ozzi

Answer:

43.2

because to convert from m/sec to kmph we need to multiply by 3600/1000

4 0

3 years ago

Cassidy Carver's family child care center has an activities table with four chairs an easel that can accommodate a child on each

Akimi4 [234]

Answer:4

Explanation:

6 0

3 years ago

Using Excel, or some other graphing software, plot the values of y as a function of x. (You will not submit this spreadsheet. Ho

Evgesh-ka [11]

Answer:

a) > x<-c(1,2,3,4,5)

> y<-c(1.9,3.5,3.7,5.1,6)

> linearmodel<-lm(y~x)

And the output is given by:

> linearmodel

Call:

lm(formula = y ~ x)

Coefficients:

(Intercept) x

1.10 0.98

b) $y = 0.98 x +1.10$

And if we compare this with the general model $y = mx +b$

We see that the slope is m= 0.98 and the intercept b = 1.10

Explanation:

Part a

For this case we have the following data:

x: 1,2,3,4,5

y: 1.9,3.5,3.7,5.1, 6

For this case we can use the following R code:

> x<-c(1,2,3,4,5)

> y<-c(1.9,3.5,3.7,5.1,6)

> linearmodel<-lm(y~x)

And the output is given by:

> linearmodel

Call:

lm(formula = y ~ x)

Coefficients:

(Intercept) x

1.10 0.98

Part b

For this case we have the following trend equation given:

$y = 0.98 x +1.10$

And if we compare this with the general model $y = mx +b$

We see that the slope is m= 0.98 and the intercept b = 1.10

7 0

3 years ago