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raketka [301]
3 years ago
13

A 2.73 kg cylindrical grinding wheel with a radius of 31 cm rotates at 1416 rpm. What is its angular momentum? Answers:

Physics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

The angular momentum of the wheel is  19.45\ kg-m^2/s.

Explanation:

It is given that,

Mass of the wheel, m = 2.73 kg

Radius of the wheel, r = 31 cm = 0.31 m

Angular speed of the wheel, \omega=1416\ rpm= 148.28\ rad/s

We need to find its angular momentum. It is given by :

L=I\omega

I is the moment of inertia of the wheel, I=\dfrac{mr^2}{2}

L=\dfrac{mr^2}{2}\times \omega

L=\dfrac{2.73\times (0.31)^2}{2}\times 148.28

L = 19.45\ kg-m^2/s

So, the angular momentum of the wheel is  19.45\ kg-m^2/s. Hence, this is the required solution.

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Explanation:

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