The problem is basically asking us to find a way to find the sound intensity I, in terms dependent on the sound level and the reference intensity
.For this purpose we can start from the unit used in the scale logarithmic decibel, that is

Where
I = Acoustic intensity on the linear scale
Hearing threshold
Using the logarithmic properties of the exponents the above expression can be described as:

that is the expression or technique to find the intensity of sound.
The part of the ignition system that amplifies the electric
voltage is the coil as it is described to be something that is joined in a
shape of a spiral or rings in a specific machine or vehicle, amplifying
electricity.
The water being poured into the bathtub is renewable and can be recycled, filtered, and renewed. But, metaphorically, each time you use electricity you drain a little water from the "bathtub" or the electric grid.
Answer:

Explanation:
Work is the product of force and distance, so the formula is:

The work is 6.00 Joules, but
- 1 Joule (J) is equal to 1 Newton meter (N*m).
- Therefore, the work of 6.00 J is equal to 6.00 N*m
The force is 2.50 Newtons.
The known values are:
Substitute the values into the formula.

We are solving for distance, so we must isolate the variable, d. It is being multiplied by 2.50 Newtons and the inverse of multiplication is division. Divide both sides by 2.50 N.


The units of Newtons cancel out.


The force was applied to the rock over a distance of <u>2.40 meters</u> and choice <u>C</u> is correct.