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rusak2 [61]
4 years ago
14

Help with math homework!

Mathematics
2 answers:
Natalka [10]4 years ago
8 0

Answer:

93\frac{24}{27}

<u>Step-by-step:</u>

86 + 7 = 93

<u>The 24 denominator stays the same and just add the numerators:</u>

\frac{14}{24} + \frac{13}{24}

= 93\frac{24}{27}

*also 14 + 13 does not equal 24, its just closest to one of the choices*

vodka [1.7K]4 years ago
5 0

Answer:

94 1/8

Step-by-step explanation:

https://www.hackmath.net/en/calculator/fraction?input=86+14%2F24+%2B+7+13%2F24&submit=Calculate

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5 0
3 years ago
16 divided[(13+7)subtract(12+ 4)]
Marta_Voda [28]

Answer:

Look below

Step-by-step explanation:

First, you solve inside the parenthesis. 13 + 7 = 20 and 12 + 4 = 16. then you do inside these []. 20 - 16 = 4. 16 divided by 4 = 4

Hope this helped.

(P.S.: if this is an essay DO NOT copy this word to word. Your teacher sees EVERYTHING (to me its creepy >.<) )

6 0
3 years ago
Read 2 more answers
Jeremy's grandfather is four times as old as he is. If you add their ages together, you will get ninety. How old is Jeremy's gra
diamong [38]
Let Jeremy's age be x
if Jeremy's grandfather is four times as old as he is,grandfather's age is 4x
if the sum of their ages is 90, we have
x%2B4x=90
5x=90
x=90%2F5
x=18->Jeremy's age
Jeremy's grandfather will be 4x=4%2A18=72
answer:
D. 72
8 0
3 years ago
The width of a rectangle is 5 feet, and the diagonal is 8 feet. Which is the area of the rectangle? (Round to nearest hundredth.
oee [108]
The \ formula \ for \ the \ area \ of \ a \ rectangle \ is: \\\\A=l\cdot w\\ where \ l \ is \ the \ length, \ w \ is \ the \ width \\\\ w = 5 \feet , \\ diagonal: \ d= 8 \ feet \\ \\ apply \ the \ Pythagorean \ Theorem:

d^2=w^2+l^2 \\ \\l^2=d^2-w^2\\\\l^2=8^2-5^2\\\\l^2=64-25\\\\l^2=39

l=\sqrt{39}\\\\l \approx 6.244998 \ feet\\\\A= 6.244998 * 5= 31.22499\approx 31.23 \ feet^2


5 0
3 years ago
Please help \^.^/<br> What is the solution to the inequality below?<br> x² =&lt; 49
gayaneshka [121]

the answer would be B. I used m a th way to find out what the answer was, you could use that app if you ever come across a similar question!

3 0
3 years ago
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