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Lemur [1.5K]
4 years ago
8

What is the half life of a radioisotope of a 50g sample becomes a 25g after 18 days?

Chemistry
1 answer:
miv72 [106K]4 years ago
7 0

18 days

<span>What does 5C on your gold ring mean?A gold ring will have the gold content inscribed inside. It mayalso have the manufacturer's mark inside. 5C would be themanufacturer's mark.</span>
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Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
3 years ago
What is the volume, in l, of 0.682 moles of o'what 2 ​ gas having a temperature of 68.2 ºc and pressure of 5.82 atm?
klemol [59]

We will use Ideal gas equation. PV=nRT where P= pressure(in atm)=5.82atm V=Volume=? n= moles of gases=0.682 R = gas constant= 0.0821L atm / mol K T = temperature= 68.2 C= 68.2 + 273.15 = 341.35 K V= nRT/ P= 0.682 X 0.0821 X 341.35/ 5.82 V= 3.284 L.  

5 0
3 years ago
Calculate the number of molecules in 64.5 grams of Nitrogen monoxide, NO
Alborosie

N=9.933

Explanation:

no of mole = m÷mr

then ,no of molecules=n×la

3 0
3 years ago
7. Which statement is true about particles in ice and in boiling water?
IceJOKER [234]

Answer:

A. particles are the same.

Explanation:

Hello, since we are talking about the water, the molecules are quite equal.

Nonetheless,  if you want to know it (because this is not in the answers), the particles move faster in the boiling water than in the ice, considering that in the boiling water there is a larger energy content, which allows the molecules to move faster (they "have" more energy). In addition, The molecules are closer in the ice because that is the only way for them to solidify (get together).

Best regards!

6 0
3 years ago
(6.0 x 10^4) (3.1 x 10^1
myrzilka [38]

Answer would be,1.86 x 10^4 hopefully that help you ❤

5 0
3 years ago
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