Answer:
K will give up an electron more easily than Br.
Explanation:
Electronegativity of an element is a property that combines the ability of its atom to lose and gain electrons.
The lower the electronegativity value, the more electropositive an element is and the more readily it loses electrons.
From the data given, we see that Br has an E.N value of 3.0 and K has an E.N value of 0.82.
Therefore, Br is highly electronegative and it is able to attract electrons to itself whereas K has a low E.N value. K will give up electrons more readily.
Lookinf at other information in the table, the larger atomic radius and lower ionizaton energy of K are all pointers to how readily it would be able to lose electrons.
We can conclude that K is even a metal.
Hi!
<u>The correct options would be: </u>
is an electron
is emitted from nucleus
has a -1 charge
Explanation:
A beta particle is a result of a neutron (a neutral particle) changing into two particles of opposite charges - a high energy electron (with a negative charge -1) and a positron (with a positive charge +1). Neutrons are present in the nucleus of an atom, and thus the beta particles are said to be emitted from the nucleus. They do have a charge, not zero, but it is not +2 and can only be either -1 or +1. This form of radiation is not electromagnetic energy because beta particles are massless, and do not travel at the speed of light (both being characteristics of electromagnetic radiation). Beta particles are not pure forms of energy.
Hope this helps.
atomic number is equal to proton number
so the proton number will be 87
To test if the hypothesis is correct, a good way is to think of it this way:
Density = mass/volume, right?
Calculate the mass and volume of each and do the equation; this will test your hypothesis.
You will be left with the density of each. But, make sure that the sample sizes are the same (controlled variable) otherwise it will be an unfair test.
valence electrons are the number of electrons in the outer shell. there can only be 8 electrons in the outer shell. The number of valence electrons can be used to determine how many bonds are needed.
For example: H2O
O (oxygen) has 6 valence electrons
H (hydrogen) has 1 valence electron
O needs 2 more electrons to be stable
H needs 1 more electron to be stable
O forms one bond with two H atoms to form H2O.
