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Dmitry [639]
3 years ago
12

What information is required to calculate the average atomic mass of an element?

Chemistry
2 answers:
STALIN [3.7K]3 years ago
8 0

All isotopes of the element their atomic masses in their relative abundance

dlinn [17]3 years ago
5 0
<span> The </span>average atomic mass of an element<span> is the sum of the </span>masses<span> of its isotopes, each multiplied by its natural abundance</span>
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How to convert 151cm to km
maw [93]
Just multiply 151 x 0.0001

That will equal:

0.00151 km or if you want to round it then it would be 0.02km
5 0
4 years ago
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1. What trends do you see when considering total electrons, valence electrons (highest occupied energy level/outermost level ele
NNADVOKAT [17]
ELECTRON CONFIGURATION

Highest occupied energy level of an element

equal to the period 
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6 0
3 years ago
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In an electrically heated boiler, water is boiled at 140°C by a 90 cm long, 8 mm diameter horizontal heating element immersed in
RideAnS [48]

Explanation:

The given data is as follows.

Volume of water = 0.25 m^{3}

Density of water = 1000 kg/m^{3}

Therefore,  mass of water = Density × Volume

                       = 1000 kg/m^{3} \times 0.25 m^{3}

                       = 250 kg  

Initial Temperature of water (T_{1}) = 20^{o}C

Final temperature of water = 140^{o}C

Heat of vaporization of water (dH_{v}) at 140^{o}C  is 2133 kJ/kg

Specific heat capacity of water = 4.184 kJ/kg/K

As 25% of water got evaporated at its boiling point (140^{o}C) in 60 min.

Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg

Heat required to evaporate = Amount of water evapotaed × Heat of vaporization

                           = 62.5 (kg) × 2133 (kJ/kg)

                           = 133.3 \times 10^{3} kJ

All this heat was supplied in 60 min = 60(min)  × 60(sec/min) = 3600 sec

Therefore, heat supplied per unit time = Heat required/time = \frac{133.3 \times 10^{3}kJ}{3600 s} = 37 kJ/s or kW

The power rating of electric heating element is 37 kW.

Hence, heat required to raise the temperature from 20^{o}C to 140^{o}C of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)

                      = 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)

                     = 125520 kJ  

Time required = Heat required / Power rating

                       = \frac{125520}{37}

                       = 3392 sec

Time required to raise the temperature from 20^{o}C to 140^{o}C of 0.25 m^{3} water is calculated as follows.

                    \frac{3392 sec}{60 sec/min}

                     = 56 min

Thus, we can conclude that the time required to raise the temperature is 56 min.

4 0
3 years ago
Which one(s) below right about valence electrons?
grandymaker [24]
Answer choice A, B, and C is right about the valence electrons. For answer choice D and E, Would in it be a more of an element kind of choice. whether the element is closer to the left side of the periodic table or not determines the high and low energy.
3 0
3 years ago
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In the alkane series of hydrocarbons, as the number of carbon atoms decreases, the normal boiling point ofthe compounds
noname [10]
<span>The relationship between the number of carbon atoms and boiling point is inversely proportional. In the alkane series of hydrocarbons, as the number of carbon atoms decreases, the normal boiling point of the compounds decreases. The reason behind this is that longer chains of molecules require more energy to separate the bonds while shorter chains or molecules with lower number of carbon atoms require less energy to break away from each other. Thus, low carbon molecules have lower boiling point.</span>
3 0
3 years ago
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