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Mice21 [21]
3 years ago
15

What are the possible orbitals for n = 3?

Chemistry
1 answer:
Tanzania [10]3 years ago
3 0

Answer:The n = 3 shell, for example, contains three subshells: the 3s, 3p, and 3d orbitals. There is only one orbital in the n = 1 shell because there is only one way in which a sphere can be oriented in space.

Explanation:hope this helps:D

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What are examples of smaller bodies ​
Inga [223]

comets, astroids oort clouds which surround the kuiper belt

8 0
3 years ago
If 78.4 grams of aluminum metal react with excess hydrochloric acid, how many grams of hydrogen gas can be produced?2al + 6hcl y
qaws [65]
Answer is: 8,7g.
Chemical reaction: 2Al + 6HCl → 2AlCl₃ + 3H₂.
m(Al) = 78,4g.
n(Al) = m(Al)÷M(Al) = 78,4g ÷ 27g/mol = 2,9 mol.
n - amount of substance.
from reaction: n(Al) : n(H₂) = 2 : 3.
2,9mol : n(H₂) = 2 : 3.
n(H₂) = 4,35 mol.
m(H₂) = n(H₂)·M(H₂) = 4,35mol · 2g/mol = 8,7g.
6 0
3 years ago
A chemist fills a reaction vessel with 9.47 atm nitrogen monoxide (NO) gas, 2.61 atm chlorine (C12) gas, and 8.64 atm nitrosyl c
lys-0071 [83]

Answer:

\Delta _rG=2832.2J/mol

Explanation:

Hello,

In this case, the Gibbs free energy of that reaction is computed by computing the equilibrium constant as:

K=\frac{p_{NOCl}^2}{p_{NO}^2p_{Cl_2}} =\frac{8.64^2}{9.47^2*2.61}=0.319

Hence the Gibbs free energy:

\Delta _rG=-RTlog(K)=-8.314\frac{J}{mol*K}*298.15K*ln(0.319)\\\\\Delta _rG=2832.2J/mol

Best regards.

3 0
3 years ago
the temperature of a balloon rises from 275 degrees k to 395 degrees k, what would the ending volume be if it started at 5 L
Airida [17]
<h3>Answer:</h3>

7.182K

<h3>Explanation:</h3>

From the question we are given;

  • Initial temperature, T1 = 275 K
  • Final temperature, T2 = 395 K
  • Initial volume, V1 = 5 L

We are required to calculate the final volume, V2

  • Charles's law is the law that relates the volume of a gas and its temperature.
  • It states that the volume of a fixed mass of a gas and its absolute temperature are directly proportional at a constant pressure.
  • Therefore;

\frac{V1}{T1}=\frac{V2}{T2}

To calculate, V2 we rearrange the formula;

V2=\frac{V1T2}{T1}

V2=\frac{(5L)(395K)}{275}

V2=7.182K

Therefore, the ending volume will be 7.182K

8 0
4 years ago
How far would Sara get if she ran for 87 minutes at a speed of .125 miles per minute?
Elza [17]

Answer:

10.875 miles

So 87 minutes

.125 miles per minute

So just multiply int his case

87*.125

You’d get 10.875

7 0
3 years ago
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