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likoan [24]
3 years ago
15

A 10.0 mL 10.0 mL aliquot is removed from the described stock solution and diluted to a total volume of 100.0 mL. 100.0 mL. Calc

ulate the molarity of the dilute solution.
Chemistry
1 answer:
andrew11 [14]3 years ago
8 0

The given question is incomplete. The complete question is:

A 10.0 mL aliquot is removed from the described stock solution with molarity of 5M and diluted to a total volume of 100.0 mL. Calculate the molarity of the dilute solution.

Answer: 0.5 M

Explanation:

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 5 M

V_1 = volume of stock solution = 10.0 ml ml

M_2 = molarity of dilute solution = ?

V_2= volume of  dilute solution = 100.0 ml

Putting in the values we get:  

5M\times 10.0=M_2\times 100.0

M_2=0.5M

Thus the molarity of the dilute solution is 0.5 M

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Explanation:

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To calculate the concentration of acid, we use the equation given by neutralization reaction:

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2\times M_1\times 10.00=1\times 0.1250\times 19.22\\\\M_1=0.1201M

Thus the concentration of the sulfuric acid is 0.1201

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