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kow [346]
3 years ago
8

PLEASE HELP I DONT UNDERSTAND AT ALLLL

Chemistry
1 answer:
xenn [34]3 years ago
8 0
The answer is C. Thank you
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In general, ionization energy will
IRISSAK [1]

Answer:

A

Explanation:

The correct answer is A.

5 0
3 years ago
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The __________ is the part of the solution that is in the greater quantity, and the __________ is the smaller portion of the sol
nikklg [1K]

Answer:

its c

Explanation:

solvent is the part of the solution that is in the greater quantity, and solute is the smaller portion of the solution

hope this helps :)

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3 years ago
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A common laboratory method for preparing a precipitate is to mix solutions containing the component ions. Does a precipitate for
laiz [17]

Answer:

CaF2 will not precipitate

Explanation:

Given

Volume of Ca(NO3)2 = 10 ml

Molar concentration of Ca(NO3)2 = 0.001

Volume of NaF = 10 ml

Molar concentration of  NaF  = 0.0001

Ksp for CaF2 = 3.2 * 10^ {-11}

CaF2 will precipitate if Q for the reaction is greater than ksp of CAF2

Moles of calcium ion

= 10 * 0.001\\= 0.01

[Ca2+] = \frac{0.01}{10 + 10} \\= \frac{0.01}{20} \\= 5 * 10^{-4}

Moles of F- ion

= 10 * 0.0001\\= 0.001

[F-] = \frac{0.001}{10 + 10} \\= \frac{0.001}{20} \\= 5 * 10^{-5}

Q = [Ca2+] [F-]^2\\= (5 * 10^{-4}) * (0.5* 10^-4)\\= 1.25 * 10^{-12}

Q is lesser than Ksp value of CaF2. Hence it will not precipitate

5 0
2 years ago
2. How many grams of zinc will be formed if 32.0 g of copper reacts with zinc nitrate? Copper(I)nitrate is the other product.
Yakvenalex [24]

Answer:

16.46 g.

Explanation:

  • It is a stichiometry problem.
  • We should write the balance equation of the mentioned chemical reaction:

<em>2Cu + Zn(NO₃)₂ → Zn + 2Cu(NO₃).</em>

  • It is clear that 2.0 moles of Cu reacts with 1.0 mole of Zn(NO₃)₂ to produce 1.0 mole of Zn and 2.0 moles of Cu(NO₃).
  • We need to calculate the number of moles of the reacted Cu (32.0 g) using the relation:

<em>n = mass / molar mass</em>

  • The no. of moles of Cu = mass / atomic mass = (32.0 g) / (63.546 g/mol) = 0.503 mol.

<u><em>Using cross multiplication:</em></u>

2.0 moles of Cu produces → 1.0 mole of Zn, from the stichiometry.

0.503 mole of Cu produces → ??? mole of Zn.

  • The no. of moles of Zn produced = (1.0 mol)(0.503 mol) / (2.0 mol) = 0.2517 mol.

∴ The grams of Zn produced = no. of moles x atomic mass of Zn = (0.2517 mol)(65.38 g/mol) = 16.46 g.

3 0
3 years ago
PLEASE HELP!!! I will mark brainliest I am really struggling with these problems
Ket [755]

Answer:

21883.75 Joules are required to melt the ice!

5 0
3 years ago
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