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FrozenT [24]
3 years ago
6

Square A and rectangle B have the same width. The length of rectangle B is 4 cm greater than its width. The area of rectangle B

is 20 cm greater than the area of square A
Set up an equation and solve it to find the area of square A.

-Thanks! :D
Mathematics
1 answer:
andre [41]3 years ago
3 0
Noting that square A is a square, this is what we have:
A = B
A^2 = B x (B + 4) + 20

I can try subbing in A to B
since A = B:

A^2 = A x (A + 4) + 20
20 = A^2 - (A x (A + 4))
20 = A^2 - (A^2 + 4A)
20 = 4A
A = 5

By the way, A is width of square A and B is the width of rectangle B in my solution,
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The quadratic function in vertex form is:

y = a(x - h)^2 + k

Where:

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The value of “h” determines how far left or right the parent function is translated.

The value of “k” determines how far up or down the parent function is translated.

Now that we have these definitions, we can substitute the given values into the vertex form to solve for “a”:

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Add 1 to both sides:

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Divide both sides by 16 to solve for “a”:

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The quadratic equation in vertex form is:

y = 1/2(x + 4)^2 - 1


Please mark my answers as the Brainliest, if you find my explanations/solution helpful :)

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Step-by-step explanation:

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