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FrozenT [24]
3 years ago
6

Square A and rectangle B have the same width. The length of rectangle B is 4 cm greater than its width. The area of rectangle B

is 20 cm greater than the area of square A
Set up an equation and solve it to find the area of square A.

-Thanks! :D
Mathematics
1 answer:
andre [41]3 years ago
3 0
Noting that square A is a square, this is what we have:
A = B
A^2 = B x (B + 4) + 20

I can try subbing in A to B
since A = B:

A^2 = A x (A + 4) + 20
20 = A^2 - (A x (A + 4))
20 = A^2 - (A^2 + 4A)
20 = 4A
A = 5

By the way, A is width of square A and B is the width of rectangle B in my solution,
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2 years ago
The size of the largest angle in a triangle is 4 times the size of the smallest angle.
Alecsey [184]

Answer: 23°, 65° and 92°

Step-by-step explanation:

a + b + c = 180 (The angles of a triangle equals to 180)

a = 4c (the largest angle is 4 times the smallest angle)

b = 4c - 27 (the final angle is 27 less than the largest angle)

c = c

Now that we have gotten the values for the variables in our equation, we plug them in:

4c + 4c - 27 + c = 180

Combine like terms:

4c + 4c + c - 27 = 180

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9c = 180 + 27

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Divide both side by 9

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b = 92 - 27

b = 65

b = 65

Check:

a + b + c = 180

92 + 65 + 23 = 180

180 = 180

8 0
3 years ago
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We can use Pythagorean’s theorem according to that:

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This is correct.


Hope it helps :)

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3 years ago
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