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yaroslaw [1]
3 years ago
15

If a real-world problem is correctly formulated, it is not possible to have alternative optimal solutions.

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0
Fat dip in the lip...........
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Is y=3x-8 proportional
Tanzania [10]

Step-by-step explanation:

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2 years ago
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For a binomial process, the probability of success is 40 percent and the number of trials is 5. Find the standard deviation.
Yakvenalex [24]

Answer:

Sd(X) =\sqrt{1.2}=1.095

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=5, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

The mean for the binomial distribution is given by:

E(X) =np=5*0.4=2

And the variance is given by:

Var(X) = np(1-p) =5*0.4*(1-0.4)=1.2

And the deviation is just the square root of the variance so we got:

Sd(X) =\sqrt{1.2}=1.095

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3 years ago
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What is x if rs= 6, st=9, tu=7, uv=15,vr=14
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8 0
3 years ago
Raquel has created a program for a robot. The robot travels 10 meters and stops. The program is designed for wheels that are 2.5
Grace [21]

Answer:

Raquel should adjust the number of rotations  to 115.81 rotations

Step-by-step explanation:

step 1

Find the circumference of the wheels that are 2.5 cm in diameter

The circumference is equal to

C=2\pi r

we have

r=2.5/2=1.25\ cm

assume

\pi =3.14

substitute

C=2(3.14) (1.25)

C=7.85\ cm

step 2

Find the number of rotations

Divide 10 meters by the circumference

10\ m=1,000\ cm

1,000/7.85=127.39\ rotations

step 3

For a diameter of 2.75 cm find how should she adjust the number of rotations so that the robot travels the same distance

Find the circumference of the wheels

The circumference is equal to

C=2\pi r

we have

r=2.75/2=1.375\ cm

assume

\pi =3.14

substitute

C=2(3.14) (1.375)

C=8.635\ cm

step 4

Find the number of rotations

Divide 10 meters by the circumference

10\ m=1,000\ cm

1,000/8.635=115.81\ rotations

3 0
3 years ago
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