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Tatiana [17]
3 years ago
12

Here is Beck's address:

Chemistry
2 answers:
choli [55]3 years ago
4 0

Answer:

D. USA

Explanation:

777dan777 [17]3 years ago
3 0

Hi! My answer would be D, USA.


Explanation:


We are provided with 5 pieces of an address. They are as followed.

12 Riverdale Lane, Apartment A, San Jose, California, and USA.


Imagine each of the five parts of Beck's address represents Earth, the Milky Way, the moon, the solar system, or the universe, based on their sizes. Which of the following parts of Beck's address would represent the solar system?



If we have to plug in Earth, the Milky Way, the moon, the solar system, and the universe, (all based on size,) we would first start with what "Apartment A" would be in this scenario. Apartment A is the smallest piece we have to work with, and so is the moon. This leads me to believe that the Moon should be plugged into Apartment A. Now, 12 Riverdale Lane is most likely going to be the Earth, since it is the second smallest one on our list. San Jose would turn into the Sun, California represents the Milky Way, and USA represents the solar system.


I sincerely hope I helped!


Have a wonderful day :)


~AmbitiousAndProud

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To calculate the molarity of NiC_2O_4, we use the equation:

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Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M

For the given chemical equations:

NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}

Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9

Net equation: NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?

To calculate the equilibrium constant, K for above equation, we get:

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The expression for equilibrium constant of above equation is:

K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}

As, NiC_2O_4 is a solid, so its activity is taken as 1 and so for C_2O_4^{2-}

We are given:

[[Ni(NH_3)_6]^{2+}]=0.016M

Putting values in above equations, we get:

0.48=\frac{0.016}{[NH_3]^6}}

[NH_3]=0.285M

Hence, the concentration of NH_3 required will be 0.285 M.

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3 years ago
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