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statuscvo [17]
3 years ago
6

A skydiver falls toward the ground at a constant velocity. Which statement best applies Newton’s laws of motion to explain the s

kydiver’s motion? An upward force balances the downward force of gravity on the skydiver. The skydiver’s inertia is zero, which no longer allows for acceleration. An unbalanced force pulls the skydiver toward the ground. The mass of the skydiver is so great that there is no acceleration.
Physics
2 answers:
Tema [17]3 years ago
7 0

Answer:

The answer is (a.) An upward force balances the downward force gravity on the skydiver

The skydiver is falling at a constant velocity because the upward force is balancing the downward force of gravity. According to Newton, the opposite force balance each other. This is stated in Newton's second law of motion.

Evgen [1.6K]3 years ago
3 0

Answer:

A

Explanation:

got it on edge

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Renewable energy sources 1.Cost more then nonrenewable resources and 2.Are so far not as reliable as nonrenewable energy.

Explanation:

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A 1400 kg car driving at 25 m/s slams on its brakes. The coefficient of kinetic friction between the tires and the road is 0.7.
tamaranim1 [39]

The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

The given parameters;

  • mass of the car, m = 1400 kg
  • Initial velocity of the car, u = 25 m/s
  • coefficient of kinetic friction, μ = 0.7

The acceleration of the car is calculated as follows;

a = μg

a = 0.7 x 9.8

a = 6.86 m/s²

The time taken for the car to stop is calculated by using Newton's second law of motion;

F = ma

F = \frac{mv}{t} \\\\ma = \frac{mv}{t}\\\\a = \frac{v}{t} \\\\t = \frac{v}{a} \\\\t = \frac{25}{6.86} \\\\t = 3.64 \ s

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

Learn more here:brainly.com/question/19887955

5 0
3 years ago
When a boy jumps into a pool ​
melomori [17]

<u>Answer:</u>

energy only

<u>Explanation:</u>

Water waves transfer energy via oscillations of the water molecules, but the the water molecules themselves do not move along the wave.

This is why when the boy jumps into the water, his kinetic energy is transferred by the water molecules across the pool, but neither the boy nor the water particles move along with the wave.

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2 years ago
Visualizing the body in the position is significant because all observers have a common point of reference when describing and d
FromTheMoon [43]

Visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.

<h3>What is the anatomical position?</h3>
  • Anatomical position, also known as conventional anatomical position, refers to the body's position while it is standing erect and looking forward, with each arm hanging on either side of the body and palms facing forward.
  • The legs are parallel, with the feet level on the floor and forward facing.
  • When explaining particular anatomical words and locations in human anatomy and physiology, the anatomical position is a standard point of reference.
  • Visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.

As the description itself says, visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.

Therefore, visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.

Know more about the anatomical position here:

brainly.com/question/5029605

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The question you are looking for is given here:

Visualizing the body in the _____________ is significant because all observers have a common point of reference when describing and discussing its region.

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A car collides head on with a stationary sign. The collision brings the car to a stop, but the sign does not move.
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A.a sign that breaks loose from the ground when a force is applied to it

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