Recall that the magnitude of the acceleration of a particle moving with speed
in a circular path around a point at a distance
away from the particle is given by
So, the satellite has velocity
pointing in the direction tangent to the circular path.
Answer:
a) 147.95 Mpc
Explanation:
Using Hubble's formula
where;
v = radical velocity
= Hubble's constant
d = distance
Given that:
The average radial velocity of galaxies in the Hercules cluster v = 10,800 km/s
Also using = 73 km/s/ Mpc ; we make distance d the subject of the formula:
Then distance d can be written as:
d = 147.95 Mpc
b)
Now, if the Hubble constant had a smaller value, then for a given velocity the distance to the galaxy will increase because distance d is inversely proportional to
i.e
d ∝
PART A)
As we know that energy of light depends on its wavelength and frequency as following formula
now we know that wavelength of blue light is less than the red light so here energy of blue light will be more
also we know that
so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium
PART B)
Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy
When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.
here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current
So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current