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Travka [436]
3 years ago
13

What is potential energy of a 10.0 kg weight suspended 3.0m above the ground?

Physics
1 answer:
Aloiza [94]3 years ago
6 0

Answer:

300 J

Explanation:

The potential energy E of an object with mass m kg,residing h meters above the ground level can be given as, E = mgh

Where g = gravitational acceleration

we can calculate,

E =10×10×3 = 300 J

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Two 2.0kg bodies A and B collide The velocities before the collision are U1=15i+30j and U2=-10j+5.0j After the collision V1=-5.0
Svetllana [295]

Use the law of conservation of momentum. Since the momentum is a linear measure, we can treat each of the dimension separately:

i-direction:

m_1u_{1i}+m_2u_{2i}=m_1v_{1i}+m_2v_{2i}\\v_{2i} = \frac{m_1u_{1i}+m_2u_{2i}-m_1v_{1i}}{m_2}=\frac{(2\cdot 15-2\cdot10+2\cdot5)kg\frac{m}{s}}{2kg}=10\frac{m}{s}

j-direction:

m_1u_{1j}+m_2u_{2j}=m_1v_{1j}+m_2v_{2j}\\v_{2j} = \frac{m_1u_{1j}+m_2u_{2j}-m_1v_{1j}}{m_2}=\frac{(2\cdot 30+2\cdot5-2\cdot20)kg\frac{m}{s}}{2kg}=15\frac{m}{s}

Answer: Final velocity is: (10i + 15j) m/s

Change in the kinetic energy:

\Delta E_k = E_{ku}-E_{kv} = \frac{1}{2}m(u_1^2+u_2^2-v_1^2-v_2^2)=\\=\frac{1}{2}2kg(1125+125-425-325)\frac{m^2}{s^2}=500J

Answer: The system lost 500J worth of kinetic energy in the collision

4 0
3 years ago
A 59kg child starting from rest slides down a water slide with a vertical height of 5.0m. what is the child's speed halfway down
KIM [24]
<span>EP (potential energy) = mgy -> (59)(9.8)(-5) = -2,891
   EP + EK (kinetic energy) = 0; but rearranging it for EK makes it EK = -EP, such that EK = 2891 when plugged in.
   EK = 0.5mv^2, but can also be v = sqrt(2EK/m).
   Plugging that in for sqrt((2 * 2891)/59), we get 9.9 m/s^2 with respect to significant figures.</span>
6 0
3 years ago
A diamond with a mass of 45 g hangs motionless from a chain. what is the upward force of the chain on the diamond?
Oksi-84 [34.3K]
The upward force of the chain on the diamond would be the tension in the chain, and this tension would have to support the weight of the 45g that hangs from the chain.

mass = 45 g = 45/1000 kg = 0.045kg

Weight = mg = 0.045 * 10 ≈ 0.45N,            g ≈ 10 m/s²

<span>So the upward force is ≈ </span><span>0.45N. </span>
6 0
3 years ago
Light travels _______ in a material with a higher index of refraction
exis [7]
Light will travel more slowly in a material with a higher index of refraction 
4 0
3 years ago
Read 2 more answers
A battery charger is connected to a dead battery and delivers a current of 3.5 a for 4 hours, keeping the voltage across the bat
oksano4ka [1.4K]
The power delivered is equal to the product between the voltage V and the current I:
P=VI=(16 V)(3.5 A)=56 W

This power is delivered for a total time of t=4h=4 \cdot 3600 s = 14400 s, so the total energy delivered to the battery is
E=Pt = (56 W)(14400 s)=806400 J=806.4 kJ
5 0
3 years ago
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