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yuradex [85]
4 years ago
8

All of the following objects are moving at the same speed. which one bas the greatest kinetic energy? (remember kinetic energy d

epends on mass and speed)
a. car


b. semi tractor-trailer truck


c. motorcycle


d. bicycle
Physics
1 answer:
melomori [17]4 years ago
6 0

B, the semi-tractor trailer truck, since it has the most mass.

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A battery of constant voltage is connected to a variable resistor. As the resistance of the resistor increases, what happens to
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with what speed does a freely falling object dropped from a height of 88.2m hit the ground? how long does it take for it hit the
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Answer:

Vf = 41.6 [m/s].

Explanation:

To solve this problem we must use the equations of kinematics.

Vf² = Vo² + (2*g*y)

where:

Vf =  final velocity [m/s]

Vo = initial velocity = 0

g = gravity acceleration = 9.81 [m/s²]

y = height = 88.2 [m]

Note: The positive sign of the equation tells us that the acceleration of gravity goes in the direction of motion.

Vf² = Vo² + (2*g*y)

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Vf = (1730.48)^0.5

Vf = 41.6 [m/s]

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3 years ago
Is lateral shift or lateral displacement same ?
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Answer:

When a ray of light passes through a glass slab of a certain thickness, the ray gets displaced or shifted from the original path. This is called lateral shift/displacement.

Explanation:

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7 0
3 years ago
A force of 7.50 N is applied to a spring whose spring constant is .298 N/cm. Find it’s length
gizmo_the_mogwai [7]

Answer:

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3 years ago
Suppose the earth suddenly came to halt and ceased revolving around the sun. The gravitational force would then pull it directly
AleksAgata [21]

Answer:

613373.65233 m/s

Explanation:

M = Mass of Sun = 1.989\times 10^{30}\ kg

m = Mass of Earth

v = Velocity of Earth

r = Distance between Earth and Sun = 147.12\times 10^{9}\ m

r_e = Radius of Earth = 6.371\times 10^6\ m

r_s = Radius of Sun = 695.51\times 10^6\ m

In this system it is assumed that the potential and kinetic energies are conserved

\dfrac{1}{2}Mv_2-\dfrac{GMm}{r_e+r_s}=0-\dfrac{GMm}{r}\\\Rightarrow v=\sqrt{2GM(\dfrac{1}{r_e+r_s}-\dfrac{1}{r})}\\\Rightarrow v=\sqrt{2\times 6.67\times 10^{-11}\times 1.989\times 10^{30}(\dfrac{1}{6.371\times 10^6+695.51\times 10^6}-\dfrac{1}{147.12\times 10^{9}})}\\\Rightarrow v=613373.65233\ m/s

The velocity of Earth would be 613373.65233 m/s

3 0
3 years ago
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