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AURORKA [14]
3 years ago
13

A woman performs 2000 J of work in order to push a cart full of groceries 50 meters. How much force did she apply to the cart?

Physics
1 answer:
Oksanka [162]3 years ago
6 0

Answer:

workdone = force x displacement

force = work done /displacement

= 2000 / 50

= 40 N .

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Pam, wearing a rocket pack, stands on frictionless ice. She has a mass of 49 kg. The rocket supplies a constant force for 22.0 m
ss7ja [257]

Answer:

Magnitude of the force is 4350N

Explanation:

As the woman accelerates at a distance of 22 m to go from rest to 62.5 m / s, we can use the kinematics to find the acceleration

v² = v₀² + 2 a x

v₀ = 0

a = v² / 2x

 a = 62.5²/(2 × 22)

 a = 88.78m/s²

the time you need to get this speed

     v = v₀ + a t

     t = v / a

     t = 62.5 / 88.78

     t = 0.704s

Let's caculate the magnitude of the force

F = ma

= 49 × 88.78

= 4350.22

≅ 4350N

Magnitude of the force is 4350N

     t = 1,025 s

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4 0
2 years ago
Water flows through a multisectional pipe placed horizontally on the ground. The velocity is 3.0 m/s at the entrance and 2.1 m/s
Stolb23 [73]

Answer:

P_1 - P_2 = 2295 pascal

Explanation:

As we know by Bernoulli's principle

P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2

P_1 - P_2 = \frac{1}{2}\rho v_2^2 - \frac{1}{2} \rho v_1^2

here we know that

\rho = 1000 kg/m^3

also we know that

v_1 = 2.1 m/s

v_2 = 3 m/s

now we have

P_1 - P_2 = \frac{1}{2}(1000)(3.0^2 - 2.1^2)

P_1 - P_2 = 2295 pascal

5 0
3 years ago
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