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Sedbober [7]
3 years ago
15

Solve the following system of equations graphically. y = 2x - 3 x + y = 3 What is the solution set?

Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0
The answer is {(2,1)}
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Add [1/5x-4+2y]+[2/5x+5-4y]=
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<h3>I'll teach you how to solve (1/5x-4+2y)+(2/5x+5-4y)</h3>

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(1/5x-4+2y)+(2/5x+5-4y)

Remove parentheses:

1/5x-4+2y + 2/5x+5-4y

Group like terms:

1/5x+2/5x+2y-4y-4+5

Add similar elements:

3/5x+2y-4y-4+5

Add similar elements:

3/5x-2y-4+5

Multiply:

3x/5-2y-4+5

Add subtract the numbers:

3x/5+1-2y

Your Answer Is 3x/5+1-2y

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3 years ago
Find ST if S(-3, 10) and T(-2, 3)
iragen [17]

Answer:

ST=(6,30)

Step-by-step explanation:

8 0
3 years ago
To fit between two Windows the width of a bookshelf must be no greater than 6 1/2 feet. Mrs. Aguilar purchases a bookshelf that
Ann [662]
To convert the measurement in feet to inches, multiply it by 12. 6 1/2 feet is equal to 78 inches. The bookshelf bought by Mrs. Aguilar has a width that is 1 inch lesser than the distance between windows. This suggests that the bookshelf will fit in the allotted space. 
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The answer is 172 cm
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Read 2 more answers
someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your
Lunna [17]

Answer:

Part A) The area of the figure is 24\ units^{2}

Part B) The perimeter of the figure is 20\ units

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

A=\frac{1}{2}bh

<u>Area of triangle ABD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(9-5)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

<u>Area of triangle BCD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(5-1)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of the figure is

12\ units^{2}+12\ units^{2}=24\ units^{2}

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+AD

we have

A(-5,1),B(-8,5),C(-5,9),D(-2,5)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units

Find the distance BC

d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units

Find the distance CD

d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units

Find the distance AD

d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units

substitute the values

P=5+5+5+5=20\ units

7 0
3 years ago
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