Question

Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station? (2 points)

Answer 1

Answer:

646.39

Step-by-step explanation:

First we would have to find our angles

90-35=55 (this would be angle A)

35-23= 12 (this would be angle B)

90+23=113 (this would be angle C)

side b was given (146 would be side b)

so we would need to find side c

to find that we use $\frac{sinB}{b} =\frac{sinC}{c},$ now plug the angles into the correct places and you should get $\frac{sin12}{146}$=$\frac{sin113}{c}$.

Next cross multiply, then your answer should look like this: csin12=146sin113

Furthermore, get the (c) by itself by dividing sin12 into both sides which would be $c=\frac{146sin113}{sin12}$.

Lastly, simplify with a calculator which is... $\frac{146sin113}{sin12} = 646.39$

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Answer 2

ANSWER:

Distance between two points W and E = 146 miles and B is the position of B (balloon)

Angle BWE =55 degrees and angle BEW =67 degrees therefore angle WBE = 180-55-67 =58 degrees

Using sine formula

w/sin (55)= b/sin(58)

w= 146{sin 55/ sin 58) =141 miles Step-by-step explanation: