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TiliK225 [7]
3 years ago
8

8. A student found the mass of an object to be 26.5 g. To find the volume, the student submerged the object in a graduated cylin

der of water. Submerging the object
in the water in the graduated cylinder increased the water level by 24.1 mL. The density of the object is
A. 0.909 g/mL.
B. 1.10 g/ml..
C.1.1 g/mL.
D. 1.0906 g/mL.
Chemistry
1 answer:
LenKa [72]3 years ago
3 0

Answer: The density of the object is 1.10 g/ml

Explanation:

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of object = ?

Mass of object = 26.5 g

Volume of object = volume of water displaced = 24.1 ml

Putting values in above equation, we get:

Density=\frac{26.5g}{24.1ml}=1.10g/ml

Thus density of the object is 1.10 g/ml

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Question 1: A substance that is soluble in two liquids and makes an emulsion last longer is called what?
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<u>Answer:</u>

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<u>Explanation:</u>

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4 years ago
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4 0
3 years ago
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Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ∆H° for the r
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Answer:

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Explanation:

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We need to find in an appropiate reference table the bond energies for all the species in the reactions and then compute the result.

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1 N≡N = 1(945 kJ/mol)     3 H-H = 3 (432 kJ/mol)       6 N-H = 6 ( 389 kJ/mol)

∆H° rxn = ∑  H bonds broken  - ∑ H bonds formed

∆H° rxn = [ 1(945 kJ)   + 3 (432 kJ) ] - [ 6 (389 k J]

∆H° rxn = 2,241 kJ -2334 kJ = -93 kJ

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